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You look at the change in the vertical distance and divide that by the change in the horizontal distance. This is known as the rise over the run. So if the line goes 4 units and over 2 units, the slope or gradient is 4/2=2. Horizontal lines have slope 0 since the rise is 0

It is my2-y1/x2-x1 the points are (9,7) (6,5) x1 y1 x2 y2 m5-7/6-9 m= -3/-3 m-0 That is the gradient

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14y ago
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12y ago

If you are finding out the gradient, then you are trying to find out the acceleration. The formula for this is acceleration = change in velocity/time.

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Q: How do you find the gradient of a straight line?
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