Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.
For this you will need a couple of helper algorithms. The first is the GCD (greatest common divisor) which is expressed as follows:procedure GCD (a, b) isinput: natural numbers a and bwhile ab doif a>blet a be a-belselet b be b-aend ifend whilereturn aThe second algorithm is the LCM (least common multiple) of two numbers:procedure LCM (a, b) isinput: natural numbers a and b return (a*b) / GCD (a, b)Now that you can calculate the GCD and LCM of any two natural numbers, you can calculate the LCM of any three natural numbers as follows:procedure LCM3 (a, b, c) isinput: natural numbers a, b and c return LCM (LCM (a, b), c)Note that the LCM of three numbers first calculates the LCM of two of those numbers (a and b) and then calculates the LCM of that result along with the third number (c). That is, if the three numbers were 8, 9 and 21, the LCM of 8 and 9 is 72 and the LCM of 72 and 21 is 504. Thus the LCM of 8, 9 and 21 is 504.
The following function will return the GCD or LCM of two arguments (x and y) depending on the value of the fct argument (GCD or LCM). enum FUNC {GCD, LCM}; int gcd_or_lcm(FUNC fct, int x, int y) { int result = 0; switch (fct) { case (GCD): result = gcd (x, y); break; case (LCM): result = lcm (x, y); break; } return result; }
The greatest number is infinity.
Count them unless the number has a recurring ending.
Another number is needed to find LCM
The LCM of this number is itself. To find the LCM requires two or more numbers.
Find the LCM of the first two numbers and then find the LCM of that number and the third one. That answer will be the LCM of all three.
You can't find the Lowest Common Multiple (LCM) of only one number. You need at least two numbers to find the LCM.
You need at least two numbers to find an LCM.
You need at least two numbers to find an LCM.
You need at least two numbers to find an LCM.
You need at least two numbers to find an LCM.
To find the LCM requires 2 or more numbers. The LCM of a single number is itself.
The LCM of one number is itself. To find the LCM requires two or more numbers.
The LCM of one number is itself. To find LCM requires two or more numbers.
The LCM of one number is itself. To find the LCM requires two or more numbers.