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Repeatedly divide the number by 10 and store the remainder (the modulo).

By way of an example, if the number were 12345:

12345 % 10 = 5 (first digit)

12345 / 10 = 1234

1234 % 10 = 4 (second digit)

1234 / 10 = 123

123 % 10 = 3 (third digit)

123 / 10 = 12

12 % 10 = 2 (fourth digit)

12 / 10 = 1 (fifth digit)

This algorithm forms the basis of number reversals. The following function demonstrates the most efficient way of reversing any number in the range -2,147,483,648 to 2,147,483,647, inclusive.

int RevNum( int num )

{

const int base = 10;

int result = 0;

int remain = 0;

do

{

remain = num % base;

result *= base;

result += remain;

} while( num /= base);

return( result );

}

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