// create an BufferedReader from the standard input stream
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String currentLine = "";
int total = 0;
// read integers
System.out.print("Input an integer: ");
while (!(currentLine = in.readLine()).equals("")) {
int input = 0;
try {
input = Integer.valueOf(currentLine);
total += input;
} catch (final NumberFormatException ex) {
System.out.println("That was not an integer.");
}
System.out.print("Input an integer: ");
}
To generate the sequence "54321012345" based on an input number ( N ), you can write a simple program that first counts down from ( N ) to 0, then counts back up to ( N ). Here's a Python example: N = int(input("Enter a number: ")) result = ''.join(str(i) for i in range(N, -1, -1)) + ''.join(str(i) for i in range(1, N + 1)) print(result) When you input ( N = 5 ), this program will output "54321012345".
#include#include#include#includeusing namespace std;string ask(string prompt){string input;coutinput)return(input);return(0);}bool ask_yn(std::string prompt){while(1){string input = ask(prompt);if( input.size() && input.size()
Not sure what you mean; if you want to measure the "input size" in bytes, that would probably be 8 bytes, since integers typically use 4 bytes.
// Get input BufferedReader in = new BufferedReader(new InputStreamReader(System.in)); String input = in.readLine(); in.close(); // Parse input int sum = 0; StringTokenizer parser = new StringTokenizer(input); while (parser.hasMoreTokens()) { int currentInt = Integer.parseInt(parser.nextToken()); System.out.println(currentInt); sum += currentInt; } System.out.println("sum = " + sum);
write a program that reads in the size of the side of square and then pints a hollow square of that size out of asterisks and blanks?
Algorithm: multiples input: two positive integers, m and n output: print first n multiples of m i = m; for j = 1 to n print i i = i + m; next j
To generate the sequence "54321012345" based on an input number ( N ), you can write a simple program that first counts down from ( N ) to 0, then counts back up to ( N ). Here's a Python example: N = int(input("Enter a number: ")) result = ''.join(str(i) for i in range(N, -1, -1)) + ''.join(str(i) for i in range(1, N + 1)) print(result) When you input ( N = 5 ), this program will output "54321012345".
#include#include#include#includeusing namespace std;string ask(string prompt){string input;coutinput)return(input);return(0);}bool ask_yn(std::string prompt){while(1){string input = ask(prompt);if( input.size() && input.size()
In a computer program, a legal input is something that can be put into a program and it will work. An illegal input may crash the program.
Not sure what you mean; if you want to measure the "input size" in bytes, that would probably be 8 bytes, since integers typically use 4 bytes.
// Get input BufferedReader in = new BufferedReader(new InputStreamReader(System.in)); String input = in.readLine(); in.close(); // Parse input int sum = 0; StringTokenizer parser = new StringTokenizer(input); while (parser.hasMoreTokens()) { int currentInt = Integer.parseInt(parser.nextToken()); System.out.println(currentInt); sum += currentInt; } System.out.println("sum = " + sum);
without understanding the program giving a input
int count_whitespace (FILE* input) { int c, count=0; while (( c = getc(input) ) != EOF ) if ((char) c==' ') ++count; return count; }
write a program that reads in the size of the side of square and then pints a hollow square of that size out of asterisks and blanks?
Create an array with 50 elements and input the integers one a time, filling the array. Use an insertion sort on the array for each input except the first. Alternatively, input the values first and then use insertion sort.
A counter is a sequencial circuit with a set of flip flop which counts the number of pulses given at the clock input A counter is a sequencial circuit with a set of flip flop which counts the number of pulses given at the clock input
create a program that can input 100 names