250 kW= 250,000 watts
1 horsepower=746 watts (The motor is approx. 335 horsepower. (just FYI))
The Ohm's Law formula for this is:
P(Power in watts)=I(Current in amps) x E(Voltage)
Since the voltage is unknown, I will give you different options based on input voltage.
I will assume three phase power for a motor this size.
So, back to the formula:
250,000=I x E
Let's assume voltage (E) to be 480v:
250,000=I x 480
I=520 amps
For a voltage of 208 (much less likely for this size motor):
250,000=I x 208
I=1201 amps
These are 'running' currents only. The amount of starting current will be much, much higher, but only for a brief period.
AnswerThe above answer assumes that the motor's input power is 250 kW. But this is not the case.
The power of a motor is always expressed in terms of its output power, not its input power! In North America, this is expressed in horse power, whereas everywhere else it's expressed in watts. So, to determine the current drawn by the motor, you have to start by determining its input power (input power is output power times efficiency); if you don't have a means of determining the motor's efficiency, then you cannot really find out its input power, in which case, you cannot find its current.
To answer your question, I need more info. What voltage are you using? IE. (12 volt, 24 volt, 120 volt, 240 volt) it makes a difference.
Use this formula ......... Watts = Amps x Volts
Amps = Watts / Volts
Volts = Watts / Amps
So figure out your voltage requirements, then use this formula to figure out
Amps Remember to give yourself a 20% margin.
Example 55 KW @ 120 Volts (55,000W / 120V = 458A)
458 - 20% = 366.4 Amps Available
Only use 80% of available Amps or Voltage otherwise your wiring
will heat-up over time and fail.
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To answer this question the voltage of the motor has to be known.
CommentYou also need to know its efficiency, because a motor is rated according to its output power*, not its input power. So, in this example, its input power will be less than 55 kW.
(*In North America a motor's output power is normally expressed in horsepower. Practically everywhere else, it's expressed in watts.)
At 2965 rpm it sounds like an induction motor for a 50 Hz supply. A 45 kW motor would draw about 55 kW from the supply with a power factor of 0.85, so that is 65 kVA, and on a 415 v 3-phase supply that is a current of 90 amps. For armoured XLPE cale the size needed is at least 16 mm2 Probably 25 mm2 would be preferred for a permanent installation but it would depend on how the cable is installed, how much free air movement there is around it etc.
75 HP = 55 KW 55 = 31/2 x 0.220 x I x cos φ = 31/2 x 0.220 x 0.8 x I I = 55/(31/2 x 0.220 x 0.8) = 180,42 A 3 x 70 mm2 is the size of cable for 75 HP 220 Volts 3 phase motor
This question cannot be answered as asked. you would need to know also the voltage and phasing. Assuming we are dealing with 120-volt, single phase, 11,500 watts would be 55-running amps. Assuming we are dealing 208-volts, three phase, 11,500 watts would be 32 running amps and assuming we are dealing with 250-volt three phase, 11,500 watts would be 26.5 running amps. I hope I have answered your question.
Outlet rating should be suitable to the rating of the motor. The type should be preferably IP 55 or higher if mounted outside the sump in dry area.
For cables in 'Free Air', that is, not routed through conduit, it depends on the Temperature rating of the cable; 60 deg C: 40 amps, 75 deg C: 50 amps, 90 deg C: 55 amps As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.Before you do any work yourself,on electrical circuits, equipment or appliances,always use a test meter to ensure the circuit is, in fact, de-energized.IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS.
55/12=4.6
Yes, a starter motor can be placed in a Vectra CDTI 55.
A number six wire, also known as 6 AWG wire, can typically hold around 55-65 amps of current, depending on the insulation type and installation conditions. It is important to follow local electrical codes and consult with a qualified electrician to ensure proper sizing and safety.
To answer this question, wire size is rated in the amount of amperage that it can legally carry. The formula to find amperage when the HP is known is I = HP x 746/1.73 x E x %eff x pf. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. Amps = 10 x 746 = 7460 = 7460/1.73 x 220 x .84 x .86 = 7460/275 = 27.1 amps. The electrical code states that a motor conductor has to be rated at 125% of the motors full load amperage. 27.1 x 125% = 33.8 A #8 copper conductor with an insulation factor of 60, 75 or 90 degrees C is rated at 40, 50 and 55 amps respectively.
A 10kW heater at 220V would draw approximately 45.45 amps. This can be calculated using the formula: Amps = Watts / Volts. So, 10,000 Watts / 220 Volts = 45.45 amps.
55 minutes at 60 mph
To calculate the amperage, use the formula: Amperes = Watts / Volts. In this case, 55 kW is 55,000 watts. So, Amperes = 55,000 watts / 460 volts ≈ 119.57 amps.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
One Megawatt = 1,000,000 watts. Watts = Volts x Amps or voltage x current. Hence if you know the voltage then Amps = 1,000,000 watts / Volts.
AWG # 6 copper
It take about 55 days.
One-tenth of an amp, if run through a human heart, would kill that person through cardiac arrest. 55 amps would probably burn a human body to ashes.