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How much ore is required to produce 1 tonne of aluminum?
It takes about 4.4 tons of bauxite ore (and about 14000 KWH of electricity) to produce 1 ton of aluminum.
What is the monthly energy cost of leaving a 60W bulb on continuously if electricity cost 10 cents kWh?
The formula you are looking for is Watts/1000 x hours in the day x cost per kWh.so it is 1,500
How many watts are in a kwh?
A 1000 watt device operated continusouly for 1 hour would equal 1 Kwh.
Does the average 2300 sq ft home in Phoenix use 3 Kw or 30 kw or 300 kws per day?
There are two measures of electricity to know about: kWh, and kW. kWh, or kilowatt-hours, is a measure of total energy use over time. It's like how far you've driven your car. kW, or kilowatts, is a measure of instantaneous consumption, like how fast you are driving at any given second. The average home in Phoenix might max out at around 3 kW or a little more when everything - your computers, refrigerator, lights, air conditioning, etc. - are running. (An individual hair dryer might use 1.5 kW, so don't run those too long.) kW, however, is not how you get billed. Almost all residential properties get billed on kWh, the total amount of electricity they use each month. kWh can be calculated by multiplying kW by the number of hours you used that kW. This is the same as figuring out how far you've driven by multiplying your speed by how much time you spent driving at that speed. In Phoenix, an average house your size might use around 30-40 kWh every day. It could be twice this in the summer when you're air conditioning, and much less in the fall or spring when you're not.
If you use 1000 kwh in a month what size solar panel system do you need?
It depends on where you live. You want to know how much Sun you get (solar hours). If you live in Southern California or Arizona, you might get 6 hours per day. If you live in Northern CA or Oregon, it might be closer to 4. First, you take your 1,000 kWh/mo and divide that by 30 to get your kWh/day. 1,000 / 30 = 33.3 kWh/day Then you divide this by the number of solar hours per day your area gets. Let's say 5. 33.3 / 5 = 6.67 kW Last you need to adjust for real world inefficiencies. A good rule of thumb is to suppose approximately 75% - 80% inefficiencies. So increase your system a little. 6.67 kW / 0.75 = 8.9 kW. This is a fairly large residential system, but you can reasonably expect it to cover 100% of your electricity needs if you use 1,000 kWh per month. Want to know how much an 8.9 kW solar system might cost? Go to and play the solar calculator in the related link below. (Yes, it's free.)
