faradays second law
how do you use ohms law express conductance in terms of current and voltage?
The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
The thicker the conductor, the less the current that will flow through.
One relationship is that both can flow in vacuum.
q=cv so current changes with change in voltage keeping c constant
Ohm's Law: voltage = current * resistance. If resistance is a constant, then voltage is directly proportional to current.
faradays second law
The current flowing through a conductor is directly proportional to the cross-sectional area of the conductor. This means that as the area of the conductor increases, the current flowing through it also increases, assuming the resistance and voltage remain constant.
inversly proportional
how do you use ohms law express conductance in terms of current and voltage?
The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
The thicker the conductor, the less the current that will flow through.
ohm
A volt is the unit of measurement for electrical potential difference, while an ampere is the unit of measurement for electrical current. The relationship between them is defined by Ohm's Law, which states that voltage equals current multiplied by resistance (V = I x R). In other words, voltage is proportional to current when resistance is constant.
There is no such equation. The main reason is that there is no relationship between current and frequency.
mass=molar mass * faradays used/faradays needed 1faraday=1C/96500 Na+(aq) + e- -> Na(s) : one electron is transferred so faradays needed to produce 23.0g Na is 1 1.4kg*1000= 1400g 1400g= 23.0g/mol * Fu/1f Fu (faradays used)= Coulombs/96500(faraday constant) Fu=60.9f=Q/96500 Q=96500*60.9= 5.88*10^6 Q=I*t 5.88*106= I*3600s(1h=60min=3600s) I=1630amps