1kva means 1kv per ampere therefore 1 amp flowing and 1 kv deduce to be the product of the two or 1kw
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Using the formula I = W/E, the current of the circuit will be 6.8 amps. As long as the wire is at least a #14 and is protected by a 15 amp two pole breaker There will be no problem. Just make sure that the specifications on the 1500 watt device clearly show that the voltage range is 220 - 240 volts. It certainly can, but it would depend on the fuse rating and existing load on the circuit.
Acid hydrolysis using sulphuric acid and water (equilibrium reaction). The ester splits into a carboxylic acid and alcohol, protons donated from the acid. The solution can then be distilled and the remaining acid can be checked using UV indicator. Acid hydrolysis using sulphuric acid and water (equilibrium reaction). The ester splits into a carboxylic acid and alcohol, protons donated from the acid. The solution can then be distilled and the remaining acid can be checked using UV indicator.
solution: Erms=100 V Irms=2 A p.f.=0.8 As per formula, Power(W)= Erms * Irms * p.f. = 100 * 2 * 0.8 = 160 W The ratio of watts average power (the average power measured in watts) to the apparent power of an alternating-current circuit. By definition, the equation below holds, which is the ratio of instrument readings. A watt-meter indicates average power, and http://www.answers.com/topic/electrodynamic-instrument or iron-vane instruments show rms voltage and current. For the steady-state ac circuit under sinusoidal voltage and current, pf = cos θ, where θ is the phase angle between the voltage and current. This definition is restricted to sine waves of the same frequency.
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5 ohms...