which r the first 10 amstrong numbers??
Here's a simple Java program that uses a for loop to generate the first 10 multiples of the first 10 natural numbers: public class Multiples { public static void main(String[] args) { for (int i = 1; i <= 10; i++) { System.out.print("Multiples of " + i + ": "); for (int j = 1; j <= 10; j++) { System.out.print(i * j + " "); } System.out.println(); } } } This program iterates through the first 10 natural numbers and prints their multiples from 1 to 10.
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
/*Program to find Armstrong number between 1 to N*/ int main() { int n = 0, remainder, sum = 0, i = 0, noDigits = 0, isArm = 0; char ch[60] = {0}; printf("Find the Arm Strong Numbers between 1 to N"); scanf("%d", &n); for(i = 1; i<n; i++) { isArm = i; itoa(isArm, ch, 10); noDigits = strlen(ch); while(isArm) { remainder = isArm%10; isArm=isArm/10; sum= sum+pow(remainder, noDigits); } if(sum == i) printf("\nArm Strong Nos are %d\n", i); sum = noDigits = 0; } }
class Armstrong{ public static void main(String args[]) { int num,rem,qub,sum=0,i; for(i=0; i<=999; i++) { num=i; sum=0; while(num>0) { rem=num%10; qub=rem*rem*rem; sum=sum+qub; num=num/10; } if(sum==i) { System.out.println("Print 1 to 1000 Armstrong Number",sum); } } } }
#include<iostream> int main() { int i=0; while(i++<10) std::cout<<i*i<<std::endl; }
Here's a simple Java program that uses a for loop to generate the first 10 multiples of the first 10 natural numbers: public class Multiples { public static void main(String[] args) { for (int i = 1; i <= 10; i++) { System.out.print("Multiples of " + i + ": "); for (int j = 1; j <= 10; j++) { System.out.print(i * j + " "); } System.out.println(); } } } This program iterates through the first 10 natural numbers and prints their multiples from 1 to 10.
Armstrong Circle Theatre - 1950 The Numbers Racket 10-13 was released on: USA: 13 April 1960
The sum of the first 10 even numbers is 110.
The sum of the first 10 counting numbers (1-10) is 51.
By adding the differences of the previous two numbers.
The sum of the first 10 odd whole numbers is 100.
The sum of the first 10 natural numbers is 51, with an average of 5.1
The numbers 4, 6, 8, 9, 10, 12, 14, 15, 16, 18 are the first ten composite numbers.
The first ten positive numbers total 55.
3.141592653
aloo
Free credit card numbers are generated automatically with computer software that generate numbers that will comply with the MOD 10 algorithm or also knows as the Luhn algorithm.