You don't say whether you're looking for the peak value of voltage or current.
-- The peak value of the sine is ' 1 ', so the peak voltage is 17 volts.
-- You haven't mentioned whether the load is complex or all real,
so naturally I'll assume it to be all real. Then the peak current is 17 volts/68 ohms = 0.25 amp.
From ohms law, I = V/R hence Voltage and Resistance can affect the value of current, both peak and average. Also with a rectifier circuit other factors can affect the peak current such as frequency and capacitance Craig - AUT
Peak to Peak is the most positive peak to the negative peak value. Or find any peak value and multiply by 2.
Unless otherwise stated, the value of an a.c. current or voltage is expressed in r.m.s. (root mean square) values which, for a sinusoidal waveform, is 0.707 times their peak value. The output of a voltage (or potential) transformer is no different, its measured voltage will be its r.m.s value which is lower than its peak value.
To find the root mean square (rms) value for a voltage given in peak-to-peak (Vpp), you need to divide the Vpp value by 2√2. In this case, the Vpp is 300mV, which is equivalent to 0.3V. Dividing 0.3V by 2√2 ≈ 2.828, the rms value is approximately 0.106 V.
rms value of ac power = dc power in reference to heat production in pure resistive load So ac power of some rms value will produce the same heat in resistive load as dc power will of same value
From ohms law, I = V/R hence Voltage and Resistance can affect the value of current, both peak and average. Also with a rectifier circuit other factors can affect the peak current such as frequency and capacitance Craig - AUT
Peak to Peak is the most positive peak to the negative peak value. Or find any peak value and multiply by 2.
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
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Unless otherwise stated, the value of an a.c. current or voltage is expressed in r.m.s. (root mean square) values which, for a sinusoidal waveform, is 0.707 times their peak value. The output of a voltage (or potential) transformer is no different, its measured voltage will be its r.m.s value which is lower than its peak value.
Peak value is the highest value ever reached.
Peak force can be calculated by dividing the peak load (the maximum force experienced during the movement) by the area over which the force is distributed. This can be determined by using a force sensor or load cell to measure the force and then calculating the peak force using the formula: Peak force = Peak load / Area.
peak - peak.
The Alernating Current can be compared to a Direct Current using the AC's Root Mean Square value. That is about .707 times the Peak value, or the sin of 45 times the peak value or, 1 over the square root of two times the peak value. All three are the same essentially. This RMS value is like the average current or voltage that the load see's throughout one cycle.
rms value of ac power = dc power in reference to heat production in pure resistive load So ac power of some rms value will produce the same heat in resistive load as dc power will of same value
No. Only less.