the denisty of water is 1000 kilograms per cubic meter. since there are 0.3048 meters in every foot, and roughly .454 kilograms in every pound the conversion works out to 62.42796 pounds of water per every cubic foot so for 1 cubic foot of water there is 62.43 pounds.
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Answer #1:
This question is easier to solve by first converting the volume to cubic centimetres (millilitres), because 1 millilitre of water weighs 1 gram and 1 litre weighs 1 kilogram.
1 ft is 30.48 cm.
1 ft * 1 ft * 1 ft
= 30.48 cm * 30.48 cm * 30.48 cm
= 28,316.8466 cm3
Now, we divide that by 1000 to convert that to litres, and knowing that 1 L weighs 1 kg of water, we get the weight.
= 28.317 kg
If you want the answer in lbs, then multiply by the number of lbs in 1 kg.
28.317 kg * 2.205 lbs/kg
= 62.43 lbs
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Answer #2:
I have a method which I claim is even easier: Look it up and memorize it.
With that method, I have been using 62.4 pounds for many years.
It has worked for me, but I confess that I am only an engineer.
1 cubic foot = 7.48 US gallons
1 gallon of water = 8.3 pounds
Therefore, 1 cubic foot of water weighs 62.084 pounds.
A square foot cannot hold water its 2 dimensional. What you see is what you get . A one cubic foot container can hold 7.48 US gallons of liquid.
Water has a density of 1 gram per cubic centimeter. There are 1,000,000 cubic centimeters in a cubic meter, so 1 cubic meter has a mass of 1000 kilograms.
0.001732
An 80-pound bag of premixed cement = .667 cubic feet, or 2/3 of a cubic foot, of concrete. A 60-pound bag of premixed cement = .5 cubic feet, or 1/2 of a cubic foot, of concrete.
The pipe diameter doesn't matter. If the pipe is discharging a cubic foot per second then it will discharge 86400 cubic feet in a day, because that is the number of seconds in one day. One acre foot is 43560 cubic feet, so the pipe discharges 86400/43560 ~= 1.98 acre feet. On the other hand, if you meant to say the water velocity exiting the pipe is 1 foot per second (not one cubic foot per second), then, assuming you have the average water velocity, you need to figure the flow rate first. The pipe has a radius of 2 in. so its cross sectional area is pi*r^2 = pi*4 ~= 12.57. So a volume of 12.57 in.^2 * 12 in. is discharged per second, which is ~ 150.80 in.^3 or about 0.09 cubic feet. From there it's the same as above. On the other other hand, if your water velocity is not the average over the cross sectional area but instead a point velocity, say at the middle of the stream of water, then you need to figure the average velocity. You'll need a hydraulics book with pipe roughness coefficients for that.