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Let us consider a tor steel of diameter 'd' mm and length 1 m

d mm=d*10^-6 m

Area of cross section,A=(3.14*d^2*10^-6)/4

Volume of steel bar of length 1 m=((3.14*d^2*10^-6)/4)*1 m

Sp.Weight of steel=7850 kg/m3

so,Weight of tor steel=((3.14*d^2*10^-6)/4)*7850 Kg

Hence 162 is nothing but a constant used for calculating weight of all type of tor steel and it is found out from;

(4*10^6)/(3.14*7850)=162

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13y ago

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