It is not a good efficiency engine.
public class olimp extends JFrame { public void paint (Graphics g){ g.setColor(Color.BLUE); g.drawOval(220, 200, 70, 70); g.setColor(Color.BLACK); g.drawOval(290, 200, 70, 70); g.setColor(Color.RED); g.drawOval(360, 200, 70, 70); g.setColor(Color.YELLOW); g.drawOval(240, 230, 70, 70); g.setColor(Color.GREEN); g.drawOval(320, 230, 70, 70); } } public static void main(String[] args) { // TODO code application logic here olimp t=new olimp(); t.setSize(600,400); t.setVisible(true); }
If this, ie 70%, is the total energy loss, it follows that the engine is producing 30% useful energy, so that is its thermodynamic efficiency.
That is the chemical formula. The name would be iron (III) oxide, or ferric oxide in the old system.
If the output power is 70% of the input power, then the output is roughly 1.55 dB downcompared to the input.If the voltage at any point of the output waveform is 70% of the voltage at the same pointon the input waveform, and the input and output impedance are equal, then the output is3.1 dB down (rounded) compared to the input.
108
360*70/100 = 252 degrees.
70 percent of what number (call the number "x") is 252, so; 0.7 * x = 252 x = 252 / 0.7 x = 360
360 divided by 70 is 5.14
100 percent of 360 is 360.
900 percent of 360 percent is 32.1
360 percent = 3.6
360-290 = 70
49 percent of 360 is 176.4
360 is 12 percent of 3000
10.83 percent of 360 = 10.8
35 percent of 360 is 126.