A typoe of research desing involving the collection of information from any given sample of population elements only ones.
The answer depends on whether the cross sectional radius/diameter are doubles or the cross sectional area is doubled.
Cell constant(C) = Resistance(R) X Specific Conductivity(K)
Resistance of a conductor is defined by the specific resistivity, area of cross section and the length of the conductor. R = rL/A, where R is resistance in OHMs, r is specific resistance, L length in mm, A is area of cross section in sq mm
It is approx 0.003068 square inches.
The relation between bending moment and the second moment of area of the cross-section and the stress at a distance y from the neutral axis is stress=bending moment * y / moment of inertia of the beam cross-section
Multiply the cross-section area by the height.
You need to know the area of that cross-section. Once you have that number, the volume of the box is the product of (cross-section area) x (height).
The formula for cross section area of a square is very easy to use. Measure the length of one side of the square it. If you are doing the cross section area of a rectangle, measure both sides and multiply them together.
Volume = cross sectional area * lengthArea = 2* cross sectional area + perimeter of cross section * length
Volume = area of cross-section*length
To find the volume of a prism you first need to know the area of cross section. Then, Volume of prism = area of cross section x length.
Imagine that you wanted to cut a globe or a sphere exactly in half. When you looked at the cut you would see an exact circle on both pieces. This area would be the cross-section. You could work out the area of this cross-section by using A = Pi X r squared. But be careful. Don't assume that the cross sectional area is the same no matter where you cut. If you cut the globe at some other point, say near to the edge, the cross-section (the circular area that you would see) would be a lot smaller. You would come across a uniform cross-section if you cut a cable. No matter where you cut the cable the cross-section should be roughly the same. Also cross section doesn't have to be circular. The cross-section you get really depends on the original shape you are dealing with. If you cut a cube in half, you would get a square cross-section. So I guess you could imagine the term as applying to cutting across (hence cross) something to reveal 2 sections (hence section).
Simply work out the area of a section of cable.........
The answer depends on whether the cross sectional radius/diameter are doubles or the cross sectional area is doubled.
The answer depends on whether the cross sectional radius/diameter are doubles or the cross sectional area is doubled.
The cross section at this point forms a circle and its area is pi/32 which equals 9*pi square units. * * * * * Not quite. If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 32) Therefore the cross sectional area is pi*(R2 - 32) square units.
just not to confuse you, here is the question more clearer: A prism has a cross section that is a regular hexagon The area of the cross section is 10.4m^2. The volume of the prism is 8.84m^2. Calculate the height of the prism.