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The cross section at this point forms a circle and its area is pi/32 which equals 9*pi square units.

* * * * *

Not quite.

If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 32)

Therefore the cross sectional area is pi*(R2 - 32) square units.

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βˆ™ 2011-11-15 14:19:53
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Q: What is the area of the cross section of a sphere that is 3 units from the center of the sphere?
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What is the radius of a cross section of a sphere that is 3 units from the center of the sphere?

If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 32) Therefore the cross sectional area is pi*(R2 - 32) square units.


What is the area of the cross section of a sphere that is 12 units from the center of the sphere?

That depends on how many units there are in the diameter of the sphere. * * * * * If the radius of the sphere is R units then the radius of the cross section is sqrt(R2 - 122) Therefore the cross sectional area is pi*(R2 - 122) square units.


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Section Modulus is moment of inertia divided by distance from center of gravity to farthest point on the cross-section or I/c. The units of Moment of Inertia is distance^4 so the units of section modulus is distance^3 ( distance cubed ). So if your units are in meters: I/c = (m^4)/(m) = m^3


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