answersLogoWhite

0

8096

What else can I help you with?

Related Questions

What is the 8086 program to find the sum of two digit n numbers?

To find the sum of two-digit numbers in an 8086 assembly program, you would typically load the two numbers into registers, add them using the ADD instruction, and store or display the result. Here's a simplified outline of the program: MOV AX, 12h ; Load first two-digit number (18 in decimal) MOV BX, 34h ; Load second two-digit number (52 in decimal) ADD AX, BX ; Add the two numbers ; AX now contains the sum (70 in decimal) This program assumes that the numbers are already defined and uses hexadecimal notation for clarity. The result can be further processed or displayed as needed.


How do you write an assembly language program to find the sum of n numbers using array?

write an assembly language program to find sum of N numbers


Java program to find sum on even numbers from 12-45?

sum = 0; for (int i = 12; i


How do you find sum of 100 numbers using fortran programme?

The following is for F95 and later (due to the use of intrinsic SUM ): My assumptions: -Your numbers are integers -Your numbers are stored in an array -The numbers you are describing are 0-100 program findSum !I assumed integer, replace this with your data type integer, dimension(100) :: numbers integer :: sumOfNumbers !We populate an array with our numbers !Replace this with your numbers do i=1,(size(numbers)+1) numbers = i end do !We find the sum of those numbers sumOfNumbers = sum(numbers) !We write out the sum to prompt write(*,*) 'Sum is: ', sumOfNumbers end program findSum


Write a C program to find the sum of all prime numbers?

Since there is an infinite set of prime numbers the answer would be infinity.


How do you write a 8086 program for the addition of a series of 8-bit numbersThe series contains 100 numbers?

To write an 8086 program for the addition of a series of 100 8-bit numbers, you can start by storing the numbers in an array in the data segment. Initialize a counter to track how many numbers have been added and a sum variable to hold the total. Use a loop to iterate through each number, adding it to the sum and incrementing the counter until all numbers are processed. Finally, store or display the result as needed. Here is a simple structure of the program: section .data numbers db 100 dup(0) ; Array of 100 8-bit numbers sum db 0 ; Variable to store sum section .text global _start _start: mov cx, 100 ; Set counter for 100 numbers lea si, [numbers] ; Load address of numbers array xor al, al ; Clear AL for sum initialization sum_loop: add al, [si] ; Add current number to AL inc si ; Move to next number loop sum_loop ; Repeat for all 100 numbers mov [sum], al ; Store the final sum ; Terminate the program (specific method depends on environment)


Shell program to find the sum of cube of individual digits of a number?

Shell problems are programs that can be run to find out information about numbers. The problem can help find an even or odd number, or what the sum of a cube is.


Program to find sum of n numbers using recursion function?

int sum(n) { if (n==0) return 0; else return n+sum(n-1); }


Write a program to find the sum of even numbers from 2 to50?

In Java:sum = 0;for (i = 2; i


Write a program that read 10 numbers from the user and display their sum?

#include<stdio.h> void main() { int num, sum=0, i; printf("Enter ten numbers: \n"); for(i=0;i<10;i++) { scanf("%d",&num); sum += num; } printf("\n The sum of the numbers is %d",sum); getchar(); }


How do you find the sum of five numbers if the average of the five numbers is 790.6?

The average of a group of numbers is equal to the sum of the numbers divided by the number of numbers. If you want to find the sum of the five numbers, just multiply 790.6 by 5 to get the sum, which is 3953


How do you find the sum?

adding numbers together has the answer to the sum.