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Complexity

prim = O(E+ V logV). E edge and V vertex.

kurskal = O(E lgV ).

Q: What is the Complexity of kruskal and prim's algorithm?

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O(E lg V)

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"What are difference between Prim's algorithm and Kruskal's algorithm for finding the minimum spanning tree of a graph?" Prim's method starts with one vertex of a graph as your tree, and adds the smallest edge that grows your tree by one more vertex. Kruskal starts with all of the vertices of a graph as a forest, and adds the smallest edge that joins two trees in the forest. Prim's method is better when * You can only concentrate on one tree at a time * You can concentrate on only a few edges at a time Kruskal's method is better when * You can look at all of the edges at once * You can hold all of the vertices at once * You can hold a forest, not just one tree Basically, Kruskal's method is more time-saving (you can order the edges by weight and burn through them fast), while Prim's method is more space-saving (you only hold one tree, and only look at edges that connect to vertices in your tree).

Both algorithms have the same efficiency and both are based on the same greedy approach. But Kruskal's algorithm is much easier to implement.

Kruskal's algorithm is an algorithm in graph theory that finds a minimum spanning tree for a connected weighted graph. This means it finds a subset of the edges that forms a tree that includes every vertex, where the total weight of all the edges in the tree is minimized. If the graph is not connected, then it finds a minimum spanning forest (a minimum spanning tree for each connected component). Kruskal's algorithm is an example of a greedy algorithm.

Related questions

O(E lg V)

o(eloge)

"What are difference between Prim's algorithm and Kruskal's algorithm for finding the minimum spanning tree of a graph?" Prim's method starts with one vertex of a graph as your tree, and adds the smallest edge that grows your tree by one more vertex. Kruskal starts with all of the vertices of a graph as a forest, and adds the smallest edge that joins two trees in the forest. Prim's method is better when * You can only concentrate on one tree at a time * You can concentrate on only a few edges at a time Kruskal's method is better when * You can look at all of the edges at once * You can hold all of the vertices at once * You can hold a forest, not just one tree Basically, Kruskal's method is more time-saving (you can order the edges by weight and burn through them fast), while Prim's method is more space-saving (you only hold one tree, and only look at edges that connect to vertices in your tree).

http://wiki.answers.com/Differences_between_prim's_and_kruskal'sexample http://wiki.answers.com/Differences_between_prim's_and_kruskal's

Both algorithms have the same efficiency and both are based on the same greedy approach. But Kruskal's algorithm is much easier to implement.

Kruskal's algorithm is an algorithm in graph theory that finds a minimum spanning tree for a connected weighted graph. This means it finds a subset of the edges that forms a tree that includes every vertex, where the total weight of all the edges in the tree is minimized. If the graph is not connected, then it finds a minimum spanning forest (a minimum spanning tree for each connected component). Kruskal's algorithm is an example of a greedy algorithm.

The correctness of either Prim's or Kruskal's algorithm, is not affected by negative edges in the graph. They both work fine with negative edges. The question boils down to "Does a Priority Queue of numbers work with negative numbers?" because of the fact that both Prim's and Kruskal's algorithm use a priority queue. Of course -- as negative numbers are simply numbers smaller than 0. The "<" sign will still work with negative numbers.

The algorithm will have both a constant time complexity and a constant space complexity: O(1)

Complexity of an algorithm is a measure of how long an algorithm would take to complete given

Time complexity and space complexity.

Dijkstra's original algorithm (published in 1959) has a time-complexity of O(N*N), where N is the number of nodes.

time complexity is 2^57..and space complexity is 2^(n+1).