What is the Program to find sum of natural number using recursion?

Answer 1

#include #define NUM 100 //since prog is to be written for adding 100 natural
int main(){
int i,sum=0;
for(i=1;i<=NUM;i++) //adding the numbers to sum, from 1 to NUM
sum+=i;
printf("SUM IS %d",sum); //printing the result
}

Answer 2

1. start

2. initialize counter (c = o)

3. initialize sum (sum = 0)

4. input n 'number of items for which average is to be calculated'

5. input the 1st (2nd, 3rd, ....) number

6 increment counter (c = c+1)

7. add the last number to sum (sum = sum+n)

8. make a decision (is counter = number of items?) yes goto 9 No goto 5

9. find average (ave = sum/n)

10. print result

11. end

Answer 3

CLS: DEFINT SUM: SUM = 0

FOR K = 1 to N

SUM = SUM + N

NEXT K

PRINT "The sum of the first "; N; "natural numbers is "; SUM; ".": PRINT

PRINT "You're welcome. The pleasure is ours. Drop in any time."

END

Answer 4

int sum( int n){

if( n==0)

return 0;

else

return n + sum(n-1);

}

A call to the function as:

sum(n)

will return the sum of n numbers.

Answer 5

The sum of the natural numbers cannot be found by any method, iterative or not, as the series is infinitely long. Please restate the question.

Answer 6

step 1. count the numbers.

step 2. sum of n numbers is n*(n+1)/2.

step 3. solve n*(n+1)/2.

Step 4. Exit