Starting at the right with the "ones", the value of each successive place doubles. So: 1, 2, 4, 8, 16 etc. The value of the place is either 0 x that number or 1 x that number. You figure out the value of each place and add them up.
So you have:
0 x 1 =0
0 x 2 =0
1 x 4 =4
1 x 8 =8
1 x 16 =16
0 x 32 =0
1 x 64 =64
1 x 128 =128
1 x 256 =256
0 x 512 =0
0 x 1024 =0
1 x 2048 =2048
0 x 4096 =0
1 x 8192=8192
_______+_____
10716
To convert a decimal number to binary in Verilog, you can use the built-in reg or wire types to store the binary value. First, define a module and declare an input for the decimal number. You can then use an assignment statement to convert the decimal to binary by assigning the input directly to the output, as Verilog implicitly handles the conversion. For example: module decimal_to_binary(input [7:0] decimal, output reg [7:0] binary); always @(*) begin binary = decimal; // Implicit conversion from decimal to binary end endmodule This code will take an 8-bit decimal input and output its binary representation.
The number 4693 in binary is 1001001010101
All I know is that when a number is negative, you convert the decimal into binary and if it is negative you put 1111 before the binary digits.
The number 6 in binary is 110
The binary values is 10110101.
170
The binary number 10101010 is equivalent, in decimal representation, to 128 + 32 + 8 + 2 = 170. But this answer assumes that the given number is binary - an assumption for which there is no real justification. Besides, the relationship is an equivalence, which is not quite "the same thing".
Decimal: 170Hex: AA
The binary code 10101010 represents the decimal number 170. In binary code, each digit is a power of 2, starting from the right with 2^0. Therefore, the binary digit 1 in the rightmost position represents 2^0, which is 1. Adding up the values of each digit in the binary code 10101010 gives 128 + 32 + 8 + 2 = 170 in decimal form.
The decimal equivalent of the binary number 1111111111111111 is 65535.
That is 31 in decimal
The binary number 1111 = 15
10
110001.01
13
45
15 = 1111