Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
public class StringReverseExample { public static void main(String[] args) { int num=1001; int n=num, rev; while(num!=0) { int d=num%10; rev= (rev*10)+d; num=num/10; } System.uot.println(rev); } }
Add the last digit plus the sum of all the previous digits. The base case is that if your integer only has a single digit, just return the value of this digit. You can extract the last digit by taking the remainder of a division by 10 (number % 10), and the remaining digits by doing an integer division by 10.
Assuming you've entered a multi-digit number whole number (an integer), then take the modus (%) of the number and 10. E.g., if the number input was 1234, then 1234 % 10 is 4. Thus the final digit is 4. Note that modus 10 is the same as dividing the number by 10 and taking the remainder.
1.382 OR 0.000 or 2831
There is no final digit to pie. It goes on forever.
You Don't know because it goes on forever!
The 1000th digit of pi is an 8.
8
1
The last digit: the 6.The last digit: the 6.The last digit: the 6.The last digit: the 6.
Not sure about milloin, but the millionth digit of pi is 5.
I will not eat that last piece of pie; I will not eat that last piece of pie; I will not eat that last half piece of pie.
Half of the last digit = 0.05 poundsHalf of the last digit = 0.05 poundsHalf of the last digit = 0.05 poundsHalf of the last digit = 0.05 pounds
It is the last digit of 34= 81. Therefore it is 1.It is the last digit of 34= 81. Therefore it is 1.It is the last digit of 34= 81. Therefore it is 1.It is the last digit of 34= 81. Therefore it is 1.
The last digit is 4.
Look at the last digit. If the last digit is even, the number is even. If the last digit is odd, the number is odd.