Pi doesn't have a last digit - it goes on for infinity (it also doesn't seem to repeat itself, so there can't even be a philosophical argument for the last digit).
Chat with our AI personalities
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
public class StringReverseExample { public static void main(String[] args) { int num=1001; int n=num, rev; while(num!=0) { int d=num%10; rev= (rev*10)+d; num=num/10; } System.uot.println(rev); } }
Add the last digit plus the sum of all the previous digits. The base case is that if your integer only has a single digit, just return the value of this digit. You can extract the last digit by taking the remainder of a division by 10 (number % 10), and the remaining digits by doing an integer division by 10.
Assuming you've entered a multi-digit number whole number (an integer), then take the modus (%) of the number and 10. E.g., if the number input was 1234, then 1234 % 10 is 4. Thus the final digit is 4. Note that modus 10 is the same as dividing the number by 10 and taking the remainder.
1.382 OR 0.000 or 2831