std::cout<<42<<std::endl;
No. Java takes some ideas from C++, so there are certain similarities, especially in the basic syntax. But it is a different language.
Its Unicode value is 221A according to System tool Character map Advanced view Unicode subrange Math operators. But I haven't done C in awhile, so I don't know how to or if you can. ASCII value of root symbol is 251. In C we can print this symbol by printing the character value as below printf("%c",251); this will print the root symbol
There is no 'foreach' in C
In C++ all false relational expressions have a mathematical value of 0.
True - A C++ constructor cannot return a value.
Yes
My self Dhilib... it is a simple query. if statement is a basic control statement. mostly it used in all the languages. also in c plus plus syntax: if(test condition) { true statements; } else { false-statements; } Example: void main() { int a,b; a=54; b=65; if(a>b) { cout<<" a value is big"; } else { cout<<"b value is big"; } }
Primarily OOP support, but there are minor syntax difference. By and large anything you can do in C you can also do in C++.
C++ Extension Name is... Syntax is: File Name.extension name. Ex: ankit.cpp
Object-oriented programming principals, a more consistent syntax and improved type-safety.
C++ uses a syntax that is exactly the same as in C, with the addition of reserved words that are specific to C++. C ++ menggunakan sintaks yang persis sama seperti di C , dengan penambahan kata-kata reserved yang khusus untuk C++.
The answer is really beyond the scope of this site. You would probably need to buy a textbook.
type variable {[optional array size]} {= optional initializer};
No. Java takes some ideas from C++, so there are certain similarities, especially in the basic syntax. But it is a different language.
It must be done by a platform-dependent function, it's "clrscr" from conio.h in TurboC
Syntax error is a kind of error when compiler does not recognize the command you are trying to use. It happens because of two reasons: first is you forgot to include required library; second is such command does not exist.
First a variable in numeric data type is to be defined. Then increment the number using the ++ command syntax of C,