Power = (voltage) x (current) = 110 x 5 = 550 watts
If operated at this level for 1 hour, then
Energy = (550 watts) x (1 hour) = 550 watt-hours = 0.55 kilowatt-hour.
Another Answer
As microwave ovens don't operate continuously, but in short bursts, it's not really possible to determine an answer to your question without knowing the frequency and duration of these bursts of energy.
kilowatt hour is the same as 1000 watt-hours. So using that principle, a 1200 watt microwave consumes 1.2 kWh of power, so in an hour it uses up 1.2 kWh of energy.
.5 kW hrs. The nominal cost would be about 5 cents.
1000 Watts * 1 hour = 1000 Watt-hours
.55 KW Hrs.
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Horse-power: convert that to kilowatt. Multiply by the time in hours you have the pump on, to get kilowatt-hours. Multiply the result by the cost of each kilowatt-hour. (Look at a recent electricity bill - if it doesn't explicitly state the cost per kilowatt-hour, you can divide the total of the bill by the number of kilowatt-hours consumed.)Amperes: You would also need the voltage. If you multiply amperes by volts, you get the power in watts. Divide the result by thousand to get kilowatts. Then continue as above.CommentAs the horsepower quoted for a machine is always its output power, you will need to know the efficiency of the machine in order to determine the input power (in watts), before performing the above calculations. The input power is always higher than the output power. Efficiency varies according to (a) the power rating of the motor, and (2) the actual load it is supplying, and can be less than 80% for smaller motors.
Electrical current is measured in amperes.
Since kilo- means one thousand, there are one thousand amperes in a kilo-ampere, and there are 0.001 amperes in a kilo-ampere.
Kilowatts means power P and amperes mean electrical current I. That does not go together. Power is not current. There is nothing equal. 1 kilowatt means 1000 watts. You can make a calculation if you know the voltage V. P = V times I I = P / V = 1000 watts / x volt
In electrical engineering it can be millivolt amperes, unless it's MVA then it is megavolt amperes. Such as in the use of large transformers.
The typical current of a microwave oven is around 10-15 amperes. It is recommended to plug the microwave into a dedicated circuit to ensure safe and efficient operation.
The voltage of the microwave can be calculated using Ohm's Law, which states V = I * R. In this case, V = 10 amperes * 5 ohms, so the voltage of the microwave is 50 volts.
Kilowatt-ampere is a unit of apparent power, which is the combination of real power (measured in kilowatts) and reactive power (measured in kilovolt-amperes reactive). It is used to describe the total power in an alternating current circuit.
To calculate the amperage of a 25-watt bulb, you need to divide the wattage by the voltage at which the bulb operates. For example, if the bulb operates at 120 volts, you would divide 25 watts by 120 volts to get the amperage.
The power required is(6) times (the amperes of current the radio draws when it operates) watts.
No, amps (amperes) do not directly express the difference in energy. Amps measure electrical current, which is the flow of electric charge. Energy is typically measured in units such as joules or kilowatt-hours.
Watts kW = (1 kilowatt = 1000 Watts) MW = (1 megawatt = 1000 kilowatts) GW = (1 giagawatt = 1000 megawatts) Volts Amperes
Electrical current is measured in amperes (A), voltage is measured in volts (V), and resistance is measured in ohms (Ω). Power is measured in watts (W), and energy is measured in kilowatt-hours (kWh).
Horse-power: convert that to kilowatt. Multiply by the time in hours you have the pump on, to get kilowatt-hours. Multiply the result by the cost of each kilowatt-hour. (Look at a recent electricity bill - if it doesn't explicitly state the cost per kilowatt-hour, you can divide the total of the bill by the number of kilowatt-hours consumed.)Amperes: You would also need the voltage. If you multiply amperes by volts, you get the power in watts. Divide the result by thousand to get kilowatts. Then continue as above.CommentAs the horsepower quoted for a machine is always its output power, you will need to know the efficiency of the machine in order to determine the input power (in watts), before performing the above calculations. The input power is always higher than the output power. Efficiency varies according to (a) the power rating of the motor, and (2) the actual load it is supplying, and can be less than 80% for smaller motors.
According to Wikipedia, all forms of power can be expressed in Watts, but typically one expresses only REAL Power in Watts (& Kilowatts).The standard is to express Apparent Power in Volt-Amperes (VA) (& KVA).The kilowatt is the unit of measure for true power; apparent power is measured in volt amperes.However, the volt ampere and the reactive volt ampere (for reactive power) are traditional units, used to help differentiate between apparent, true, and reactive power. SI recognises the watt as the unit for each.
To calculate the amperes for a fluorescent lamp using VA (volt-ampere), you can divide the VA rating by the voltage of the lamp. The formula is: Amperes = VA / Voltage. For example, if a fluorescent lamp has a VA rating of 60 VA and operates at 120 volts, the amperes would be 0.5A (60 VA / 120V).
15500 nano amperes or .0155 milli amperes or .0000155 amperes