The total load in watts would be W = A x V. 20 x 120 = 2400 watts. Any wattage higher than this will trip the breaker and shut the circuit off.
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The theoretical resistive load is V/I = 120/20 = 6 Ohms. The lower the resistance the higher the current. Usually you don't want to operate above the 80% point so the number would be 120/16 = 7.5 Ohms.
Usually you de-rate the amperage by 20% of capacity hence let's assume 16A max. Assuming 120 V as the voltage and using Ohm's Law (V = Current x Resistance) you have 120 / 16 = R. Therefor the resistive load = 7.5 Ohms. If you were looking for a light bulb equivalent and were using 60 Watt bulbs at 16 A you could light 32 bulbs, each drawing 1/2 A.
Question is incorrect. in a 240 Volt single phase circuit, how can you have A phase and B phase?
If you are talking about a 6 volt coil, yes, so long as the contacts are rated for the 230 volt circuit. If you are talking about 6 volt contacts, no, absolutely not.
It all depends on the load. The formula for calculating amps, volts or ohms (resistance of load) is E=IR, where E is the voltage, I is the current and R is the load or circuit resistance. So, if you know the resistance in ohms and the current in amps, you multiply them together to get the voltage of the circuit. Again, it depends on the load, so a 12 volt car battery can deliver 1.5 amps if the load is 8 ohms whereas a 120 volt circuit will deliver 1.5 amps if the load is 80 ohms. This is all simplified and is based on a resistive load. If the load is capacitive or inductive, then phase angles come into play and the math is more complicated using imaginary numbers and J-operators.
7 ohms (5+1+1)
1 volt
Volt-Amp (VA) is a unit of measurement for apparent power in an electrical circuit, representing the total power consumed by a device. It is the product of voltage (in volts) and current (in amperes) in an AC circuit. VA is important for sizing power supply equipment to meet the demands of the electrical load in a system.
The current in a 220 volt circuit depends on the resistance of the load connected to it. Ohm's Law (I = V/R) states that current (I) is equal to voltage (V) divided by resistance (R). So, the current will vary based on the resistance of the circuit.
To calculate the amperage in a circuit with a power of 6kW on a 240-volt supply, you can use the formula: Amperage (A) = Power (W) / Voltage (V). In this case, the amperage would be 25A. This calculation is based on the relationship between power, voltage, and current in an electrical circuit, as defined by Ohm's Law.
Question is incorrect. in a 240 Volt single phase circuit, how can you have A phase and B phase?
A volt can not be connected to a circuit.
AWG # 10 wire on 30 amp circuit.
When you mean simple circuit, I assume a source of one volt across a load of one ohm, which, according to Ohm's Law, equals one amp.
resistance = volt / current . 440 volt across a parallel circuit means the same 440 volt across both resistance s. hence resistance r = volt / current . 440 / 20 amp = 27.5 ohms total resistance
Placing a voltmeter into a circuit will not raise the circuit resistance. A voltmeter is designed to have a very high resistance so that it does not significantly affect the circuit being measured. The resistance of the voltmeter is much higher than the resistance of the circuit, so it has minimal impact on the overall resistance of the circuit.
Series circuit? Add 'em!
LxW of building x 3 volt amps per sq. foot
LxW of building x 3 volt amps per sq. foot