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The total load in watts would be W = A x V. 20 x 120 = 2400 watts. Any wattage higher than this will trip the breaker and shut the circuit off.

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The theoretical resistive load is V/I = 120/20 = 6 Ohms. The lower the resistance the higher the current. Usually you don't want to operate above the 80% point so the number would be 120/16 = 7.5 Ohms.

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14y ago
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14y ago

Usually you de-rate the amperage by 20% of capacity hence let's assume 16A max. Assuming 120 V as the voltage and using Ohm's Law (V = Current x Resistance) you have 120 / 16 = R. Therefor the resistive load = 7.5 Ohms. If you were looking for a light bulb equivalent and were using 60 Watt bulbs at 16 A you could light 32 bulbs, each drawing 1/2 A.

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13y ago

For continuous duty you want to derate the current to 80% of max or 12 Amps in this case. Using Ohm's Law where Volts = Amps x Resistance the resistance would be 10 ohms. For a resistive load that would equate to 1,440 watts.

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14y ago

The formula you are looking for is W = A x V.

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12y ago

A 20 amp circuit will handle any loads up to 20 amps. Any loads above 20 amps will trip the circuit protection and open the circuit. A 20 amp circuit requires a #12 copper conductor.

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13y ago

80% of 20 Amps or 16 Amps.

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Q: What is the total load allowed on a 20 amp 120 volt circuit?
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