yes the motor will run but will draw more current and the torque will be not constant means not smooth due to unbalanced current
The bulb with the lowest resistance. Current = Volts / Resistance
Look on the motor's chart for "Locked rotor current" its going to be high because the motor is trying to overcome infinite inertia. Any motor will draw 8 - 10 times its rated current upon start up because you are overcoming inertia. It takes more energy to start any system than it does to keeping it running.
Depends on how big the motor is. A stronger motor will draw more amps then a weaker or less efficient motor. For example a wiper motor draws far less then a starter motor.
As anything to do with timing values for an electronic system of controlling a motor. Based on the question, the simple answer is that the capacitor causes a 90 degree lead which allows the motor to have a magnetic shift which causes the motor to start rotation.
Excessive resistance (drag), will cause motor to draw more amps (current flow) to operate.
yes the motor will run but will draw more current and the torque will be not constant means not smooth due to unbalanced current
when the motor runs more than rated speed it produces leading current and results act as a generator. (or) the motor act as generator when it produces more back e.m.f
defective motor will not run, also cause the blower motor speed resistor to burn out and eventually blow the fuse. a motor with defective bearings will draw excessive current causing either the fuse to blow or cause the motor to overheat
It will run hotter. It will run slower, about 83% of nameplate speed. It will draw more than the nameplate current. You will only be able to get about 3/4 of rated horsepower. If the motor is loaded to more than this, it will not live very long.
This is done under blocker rotor test of induction motor in which the rotor of the motor is stopped by some external mechanical means and the supply is increased slowly from the autotrasformer until the rated motor current is reached and the V , I ,W readings are taken . As the rated current flows the winding temperature increases but upto rated current this temperature rise is within the safe limits . In the blocked rotor condition the rated current is achieved at around 20-25% of the rated supply voltage . If we further increase the voltage then the current flowing is more than it's rated or permissible value so windings get dengerously hot and they get burnt or damaged .
In large motors, the no-load current is higher because the motor needs to overcome the friction and windage losses present when running without a load. These losses require more power to overcome, resulting in a higher current draw. When the motor is under a load, the additional power required to turn the load increases the current draw further.
The bulb with the lowest resistance. Current = Volts / Resistance
Look on the motor's chart for "Locked rotor current" its going to be high because the motor is trying to overcome infinite inertia. Any motor will draw 8 - 10 times its rated current upon start up because you are overcoming inertia. It takes more energy to start any system than it does to keeping it running.
I would guess by overloading or by running at too low a voltage which has the same effect.The amperage goes beyond the rated amperage if overloaded. If undervoltage but heavily loaded then the motor will attempt to draw more current to make up the loss in power and exceed the rated current.In either case the excess current saturates the magnetics and overheats the motor causing insulation breakdown on the windings (and that horrible smell) and you get what is popularly known as burnout. Once the insulation has broken down the motor loses most of its torque and would be considered failed.
As we know that P=VI, and P is a constant value for any particular motor, so if the voltages will drop current will increase so that the product of V and I be the that particular constant value for any particular motor
A motor's service factor is a multiplier applied to a motor's horsepower rating to indicate the level of overload it can handle. The motor's nameplate amperage rating indicates the maximum current it should draw under normal operating conditions. The service factor does not directly impact the amperage rating, but motors with a higher service factor may be capable of handling higher loads and thus draw more current.