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# Which important property do stack algorithm have?

Updated: 10/27/2022

Zhen

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They will scratch and mess up. They will scratch and mess up. They will scratch and mess up. They will scratch and mess up. They will scratch and mess up. They will scratch and mess up.

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rayleen garrido

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rayleen garrido

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Q: Which important property do stack algorithm have?
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### Design an algorithm to show the different operations on a stack?

Design an algorithm to show the different operations on a stack?

### What is the importance of stack algorithm in your program?

Stack implementations allow us to easily implement backtracking algorithms.

### What are Disadvantage of stack?

A stack is a LIFO (last-in, first-out) data structure such that only the top-most element is accessible and all new elements are pushed onto the top (analogous to a stack of plates). Stacks are advantageous when implementing a back-tracking algorithm but are ultimately useless for anything else. However, this is not a disadvantage. If you're not implementing a back-tracking algorithm then the problem is not the stack itself it is the fact that you are using the wrong type of container for your algorithm.

### An algorithm to Reversing the order of elements on stack S using 1 additional stacks?

// stack to contain content Stack sourceStack = new Stack(); // ... fill sourceStack with content // stack to contain reversed content Stack targetStack = new Stack(); while (!sourceStack.empty()) { targetStack.push(sourceStack.pop()); } // targetStack contains the reversed content of sourceStack

### What is a stock sorting algorithm?

Stock sorting algorithm is a algorithm which is used to sort any kind of stock i.e. any data type containing the primitive values like array ,link list ,stack etc.

### What is stock sorting algorithm?

Stock sorting algorithm is a algorithm which is used to sort any kind of stock i.e. any data type containing the primitive values like array ,link list ,stack etc.

### Can you provide a solution to the diamond-square algorithm using Java and recursion?

Yes. It is possible to provide a solution to the diamond-square algorithm using Java and recursion.

### One very best property of algorithm?

One of the best property of an algorithm is that it is simple. It can not be too long and ambiguous, it has to be straightforward, with understandable variables as used also in a pseudocode.

### How do you overcome limitations of stacks in polygon filling?

You overcome limitations of the stack in polygon filling, or in any other algorithm, far that matter, but using an iterative technique, rather than a recursive technique. Recursion is quite useful, and can simplify algorithm design. Polygon filling, however, is a class of algorithm can potentially have a very deep recursion depth. This causes stress on the stack, hence the need for iteration.

### Algorithm for conversion from prefix to infix?

The belt-and-braces technique is easy enough: &gt; &gt; prefix_to_infix(stream, stack) &gt; if stack is not empty &gt; pop a node off the stack &gt; if this node represents an operator &gt; write an opening parenthesis to stream &gt; prefix_to_infix(stream, stack) &gt; write operator to stream &gt; prefix_to_infix(stream, stack) &gt; write a closing parenthesis to stream &gt; else &gt; write value to stream &gt; endif &gt; endif &gt; endfunc

### Algorithm for implementing push operation on stack?

1. If TOP = MAXSTK THEN [Stack already filled?] Print "OVERFLOW" Go to step 4 Endif 2. TOP = TOP + 1 [Increase TOP by 1] 3. Set ST[STOP] = ITEM [Insert ITEM in new TOP position] 4. End

### Write an algorithm to remove an item from the top of the stack?

It is not possible to write a code to POP from the stack when there is no your stack implementation information.Because of that I am going to talk more about Stack in computer architecture and there will be additional link to specific examples(-e).In x86 architecture there is three registers (BP, SP and SS) which are connected with stack and only SP and SS is needed.SS - Stack Segment (base register);SP - Stack Pointer (offset);This is how the POP instruction works:# operand = [SS:SP] (top of the stack) # SP = SP + 2; (change SP to point to new top element)