Write 8085 assembly language program to find the 2's complement of a given 8 bit integer?

Answer 1

Solution:

CLR C ;make CY=0

MOV A, #0E7H ;load the low byte now A=E7H

ADD A, #8DH ;add the low byte

MOV R6, A ;save the low byte sum in R6

MOV A, #3CH ;load the high byte

ADDC A, #3BH ;add with the carry

MOV R7, A ;save the high byte sum

Answer 2

LDA 4200h

cma

adi, 01h

STA 4300hhlt

Answer 3

LXI H.2500

LXI D 2601

MOV B,M

*CALL 2300

STAX D

CALL 2400

INX D

DCR B

JNZ*

HLT

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Answer 4

mov ax,firstnumber add ax,secondnumber mov result,ax

Answer 5

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