Here's a simple Java method to perform the conversion from decimal to a binary string representation:
public String toBinaryString(int n) {
StringBuilder sb = new StringBuilder();
while(n != 0) {
sb.insert(0, n % 2 != 0 ? '1' : '0');
n /= 2;
}
return sb.toString();
}
The java.lang.Integer class provides a conversion helper method between decimal (integer) and binary numbers in string form called toBinaryString().
String binaryValue = Integer.toBinaryString(43) // 43-> "101011"
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You can't. While Java supports hexadecimal and octal literals, there is no native support for binary. You need to use/write a method to do the conversions for you.
write a c++ program to convert binary number to decimal number by using while statement
Write algorithms and draw a corresponding flow chart to convert a decimal number to binary equivalent?
This is not a question.
k n o w ? First convert it to ASCII code ... 107 110 111 119 (all decimal numbers) Then convert to binary : 1101011 1101110 1101111 1110111
This is not a perfect program, but it will get you started in the right direction. Works for any INTEGER up to "some" power of 2 (decimals kill the program). PROGRAM binary IMPLICIT NONE INTEGER remainder, quotient, n, int_input, answer REAL input, dec_input WRITE(*,*) 'Input a number to convert to binary' READ(*,*) input int_input = input dec_input = input - int_input dec_input = abs(dec_input) quotient = abs(input) DO WHILE (dec_input==0) n = 0 answer = 0 DO WHILE (quotient>1) remainder = mod(quotient,2) quotient = quotient/2 answer = answer+remainder*10.**n n = n+1 END DO IF (input<0) answer = -answer answer = answer + quotient*10.**n WRITE(*,"(a,i31)") 'Your answer in binary is:',answer END DO END PROGRAM binary