Here's a simple Java method to perform the conversion from decimal to a binary string representation:
public String toBinaryString(int n) {
StringBuilder sb = new StringBuilder();
while(n != 0) {
sb.insert(0, n % 2 != 0 ? '1' : '0');
n /= 2;
}
return sb.toString();
}
The java.lang.Integer class provides a conversion helper method between decimal (integer) and binary numbers in string form called toBinaryString().
String binaryValue = Integer.toBinaryString(43) // 43-> "101011"
write a c++ program to convert binary number to decimal number by using while statement
Write algorithms and draw a corresponding flow chart to convert a decimal number to binary equivalent?
k n o w ? First convert it to ASCII code ... 107 110 111 119 (all decimal numbers) Then convert to binary : 1101011 1101110 1101111 1110111
This is not a question.
This is not a perfect program, but it will get you started in the right direction. Works for any INTEGER up to "some" power of 2 (decimals kill the program). PROGRAM binary IMPLICIT NONE INTEGER remainder, quotient, n, int_input, answer REAL input, dec_input WRITE(*,*) 'Input a number to convert to binary' READ(*,*) input int_input = input dec_input = input - int_input dec_input = abs(dec_input) quotient = abs(input) DO WHILE (dec_input==0) n = 0 answer = 0 DO WHILE (quotient>1) remainder = mod(quotient,2) quotient = quotient/2 answer = answer+remainder*10.**n n = n+1 END DO IF (input<0) answer = -answer answer = answer + quotient*10.**n WRITE(*,"(a,i31)") 'Your answer in binary is:',answer END DO END PROGRAM binary
write a c++ program to convert binary number to decimal number by using while statement
How is this a question? Sounds like you should do more of your homework offline.
Write algorithms and draw a corresponding flow chart to convert a decimal number to binary equivalent?
You can use a table to convert binary to decimal & back:MSBBinary DigitLSB2827262524232221202561286432168421Figure out the greatest power that will fit into the number you want to convert to binary. Move to the next lower power of two. If you can fit into the next lower number write down a "1", if it can't put down "0". Put together the binary answer.
Decimal 23 is 10111 in binary
Decimal 18 is 10010 in binary
Decimal 26 is 11010 in binary
Decimal 27 is 11011 in binary
When you write the decimal number '7' in Base-2 (binary), you write '0111'.
k n o w ? First convert it to ASCII code ... 107 110 111 119 (all decimal numbers) Then convert to binary : 1101011 1101110 1101111 1110111
This is not a question.
pongada punda vayanungala ..................