Write a program in c language to subtract two numbers?

Answer 1

Just declare, initialize, and subtract...

double a = 1.23456789;

double b = 2.34567890;

double c;

c = a-b;

Answer 2

#include<stdio.h>

#include<conio.h>

int main(void)

{

int sum=0,n,i;

clrscr();

printf("\n Enter two no.");

scanf("%d%d",&n,&i);

sum=n+i;

printf("\n%d+%d=%d,n,i,sum);

getch();

return 0;

}

Answer 3

#include

#include

void main()

{

int a,b,c;

clrscr();

printf("enter a ,b values:");

scanf("%d%d",&a,&b);
c=a+b;

printf("the addition of two no is:",c);

getch();

}

Answer 4

//write a program for subtraction of 2 numbers.

#include

main()

{

int a,b,d;

printf("enter 2 numbers :");

scanf("%d%d",&a&b);

d=a-b;

printf("subtraction of 2 numbers=%d",d);

}

output(example)-

enter 2 numbers : 3 2

subtraction of 2 numbers : 1

Answer 5

#include<stdio.h>

#include<conio.>

void main()

{

int a,b,sum;

clrscr();

cin<<"enter value of a";

cout>>a;

cin<<"enter value of b";

cout<<b;

sum=a+b;

cout<<"sum of two numbers="

getch();

}

Answer 6

//program to add two numbers

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,c;

clrscr(): //its prototype or header file is conio.h

printf("\n enter first number :"); //its prototype or header file is stdio.h

scanf("%d",&a); //its prototype or header file is stdio.h

printf("\n enter second number :"); //its prototype or header file is stdio.h

scanf("%d",&b); //its prototype or header file is stdio.h

c=a+b;

printf("\n the sum of two numbers is :%d",c); //its prototype or header file is stdio.h

getch(); //its prototype or header file is conio.h

}

Answer 7

Use ~ Ones complement operator and add one.

10 - 3 = 7

10 + ~3 + 1 = 7

GP>

Answer 8

int num0 = 0;

int num1 = 1;

int num2 = num1 - num0;

Answer 9

wap to subtract two variables