Write a program to find the average of three numbers using c language?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,c;

float avrg;

printf("enter the first number:");

scanf("%d",&a);

printf("enter the second number:");

scanf("%d",&b);

printf("enter the third number:");

scanf("%d",&c);

avrg=(a+b+c)/3.0;

printf("The average of given numbers is:%f",&f);

getch();

}

this c program is specifically for three variables only.

Answer 2

#include <stdio.h> #include <stddef.h>

int main() { int a,b,c; printf("Enter three numbers"); if( scanf("%d %d %d",&a,&b,&c) == 3 ) { a += b + c;

printf("The sum is %d",a);

} else { printf("Invalid input!\n" Bye!\n\n"); exit(EXIT_FAILURE); } return EXIT_SUCCESS;

}

Answer 3

main ()

{

/* create memory spaces for variables */

int integer_one, integer_two, integer_three, integer_sum;

/* initialize variables */

integer_one = 5; integer_two = 7; integer_three = 8;

/* Sum the variables */

integer_sum = integer_one + integer_two + integer_three;

/* print the variables */

printf ("answer is %d", integer_sum);

}

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- Anything with /* or */ is a comment

- This 'program' allows for no input, just output. To get it interactive you'd have to use getc to get the keystrokes then add them.

Answer 4

#include<stdio.h>

#include<conio.h>

// Declaration of function

float add(float,float,float);

//definition of function

float add(float a,float b, float c)

{

float x;

x=a+b+c;

return x;

}

// main function

void main()

{

float a,b,c,x;

printf("Enter three numbers");

scanf("%f,%f,%f",&a,&b,&c);

x=add(a,b,c);

printf("The addition is %f",x);

getch();

}

Answer 5

The same way you do it in any language: divide the sum by three.

int x, y, z, average;

x = 1;

y = 3;

z = 5;

average = (x+y+z)/3;