Write a programe to find whether a number is odd or even?

Answer 1

#include
#include

int main(int argc, char *argv[]){
if(argc != 2) {
printf("pass one integer as an argument.\n");
exit(1);

}
if(atoi(argv[1]) % 2){
printf("That is an odd number\n");

}else{
printf("That is an even number\n");

}
return 0;

}

Answer 2

CLS

PRINT "PROGRAM: Find if number is odd/or, even"

PRINT

INPUT "Enter number: ", number$

number% = VAL(number$)

PRINT

PRINT "The number is ";

IF number% MOD 2 = 0 THEN

PRINT "even."

ELSE

PRINT "odd."

END IF

END

Answer 3

In twos-complement notation, if the least-significant bit is set, then the number is odd, otherwise its even.

In ones-complement notation, positive values follow the convention of twos-complement values while negative values use the opposing convention, if the least-significant bit is set then the number is even, otherwise it is odd.

A slower method but one that is common to both ones-complement and twos-complement is to use the modus of the value. The modus of a value is the remainder after dividing by another value. If the other value is 2 then the modus can only be 0 (even) or 1 (odd).

Answer 4

In Java:

if (myNumber % 2 == 0)

System.out.println("The number is even.");

else

System.out.println("The number is odd.");

Similar in C or C++. The % operator is also used to check the remainder of a division, but you would have to change the output command.

Answer 5

Get number

Divide number by 2 and store remainder

if remainder equal 0 print "Even"

if remainder equal 1 print "odd"

end program

Answer 6

I need the program that can display this number

4

12

44

444

5555

66666

Answer 7

bool IsNumberEven(int number)

{

if (number%2 == 0)

return true;

return false;

}

Answer 8

Number = Val(Textbox1.text)

If Number Mod 2 = 0 then

MsgBox("It is even.")

End If

If Number Mod 2 <> 0 then

MsgBox("It is odd.")

End If

Answer 9

void main()

{

int n;

printf("enter number :- ");

scanf("%d",&n);

(n%2==0)?"number is even" : "number is odd ";

getch();

}