Write a pseudocode to find the greatest of two numbers?

Answer 1

Begin

read a,b

if a>b

display a is greater

else

display b is greater

end

Answer 2

Sure thing, honey! Here's a quick and dirty pseudocode for ya:

function findGreatest(num1, num2)
    if num1 > num2
        return num1
    else
        return num2

There you have it, simple and straight to the point. Now go out there and find those big numbers, tiger!

Answer 3

Certainly! Here's a simple pseudocode to find the greatest of two numbers:

1. Start
2. Input first number as num1
3. Input second number as num2
4. If num1 is greater than num2
5.    Display num1 as the greatest number
6. Else
7.    Display num2 as the greatest number
8. End

This pseudocode first takes two numbers as input, then compares them using an if-else statement to determine which is greater, and finally displays the greatest number.

Answer 4

#include

using namespacestd;

int main()

{

//declaration of your numbers

double firstNumber = 0, secondNumber = 0;

cout << "Enter your first number: ";

cin >> firstNumber;

cout << "Enter your second number: ";

cin >> secondNumber;

if (firstNumber > secondNumber)

{

cout << "First number is greater!\n";

}

else if (firstNumber < secondNumber)

{

cout << "Second number is greater!\n";

}

else

{

cout << "The number are equal!\n";

}

cin.get();

return 0;

}

Answer 5

#include<iostream>

using namespace std;

class num

{

friend num& largest(num& a, num& b);

friend ostream& operator<<(ostream&, num&);

public:

num (int data=0): m_data(data){}

bool operator< (const num& other) { return m_data<other.m_data; }

private:

int m_data;

};

num& largest (num& a, num& b) { return a<b?b:a; }

ostream& operator<< (ostream& os, num& n) { os << n.m_data; return os; }

int main()

{

num x = 42;

num y = 24;

cout << "The largest of " << x << " and " << y << " is " << largest (x,y) << endl;

}