Algebraically, it is ; - A = pi r^(2) In words, it is ' Area equals 'pi' multiplied to the radius squared'. NB 'pi' is a constant at 3.141592..... usually shortened to '3.14'. The radius (r) is the distance from the circle centre to the circumference/edge. 'radius squared' is r^(2) , that is 'r' multiplied to 'r' ; r X r = r^(2) . NNB The circumference of a circle is ; C = 2 pi r Note the power/exponent of '2' becomes a coefficient. In words ' Circumference equals two multiplied to 'pi' multiplied to the radius. (NOT radius squared).
V of a circular slab = thickness of the slab multiplied by (pi multiplied by the radius2)
Formula for area: A = Pi*R² (Pi = 3,1416 and R² is the radius multiplied by itself) Formula for circumference: C + Pi*D (D is diameter) Formula for Diameter: D = 2*R (radius multiplied by 2))
Circumference = Diameter multiplied by Pi Diameter = Circumference divided by pi Radius = Diameter divided by 2.
divide dy pi. the rule is diiameter (or 2 radius) multiplied by pi equals circumference so: 2 pi x radius= circ and, since diameter is 2 times the radius, pi x D= circ
Because the circumference is equal to the diameter multiplied by pi or the radius multiplied by 2*pi.
1/3 multiplied by pi multiplied by radius squared multiplied by height
The answer is 12.56
449184.53
24.492, unless you want more digits of pi besides the standard 3.14. The circumference of a circle is equal to the diameter multiplied by pi, or the radius multiplied by two, then multiplied by pi. c = d*pi c = 2*r*pi c = circumference d = diameter r = radius pi = 3.141593
pi multiplied by r squared multiplied by height
Do you mean volume or surface area? volume = 4/3 x pi x r^3 (four divided by three, multiplied by pi, multiplied by radius cubed). surface area = 4 x pi x r^2 (four multiplied by pi, multiplied by radius squared).
8.53973 (rounded)
25.12 dah
Pi multiplied by the Diameter.
Yes. 1/pi. pi x 1/pi = 1.
Maybe. It depends on the number that you are multiplying. Pi multiplied by (1 / 4pi) = 1/4. A quarter is definitely rational.