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A block is at rest on an inclined plane. Find the critical angle at which the box beigns to slide?
Wiki User
∙ 12y ago
tan-1(MUs)= critical angle
Wiki User
∙ 12y ago
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A 5.0 kg wooden block is placed on an adjustable wooden inclined plane. What is the angle of incline above which the block will start to slide down the plane .57?
mgsin (theta) - (static) mu * mgcos(theta) = 0 rearrange the equation and cancal mg therefore, tan ( theta) = mu (static) theta = arctan (static mu) If the static coefficient is 0.57, then theta = arctan (0.57) theta = 29.7 degree Note: from the equation, the mass of the block is independent to the angle. Whether you have a bigger block or smaller block, it will start sliding @ 29.7 degree.
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How can an adjustable inclined plane be used to measure the coefficient of static friction and coefficient of static friction with a mass of 5.0?
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