Assuming the radius is an inside dimension: The inner surface area of the cylinder is Pi x R² = 3.1416 x (3 x 3) = 3.1416 x 9 = 28.2744 sq cm. The area is multiplied by the depth of the sand to find its volume. 28.2744 sq cm x 1 cm = 28.2744 cu cm.
The volume of a cylinder is V=PI*r2*h The radius of the cylinder is 3 cm and the height would be 1cm So V = PI*(3cm)2*(1cm) V is approx. 28.3 cm3
100 cubic cm
each layer will have (4*4) cubes = 16 and 2*16 is 32 so there are 2 layers which means the height of the box is 2 cubes
screed
the upper layer of the earth's mantle
The volume of a cylinder is V=PI*r2*h The radius of the cylinder is 3 cm and the height would be 1cm So V = PI*(3cm)2*(1cm) V is approx. 28.3 cm3
The volume of sand in the cylinder is the area of the circular base multiplied by the height of the layer. The area of the circular base is πr^2, where r is the radius (3 cm), and the height of the layer is 1 cm. So, the volume of sand is π * 3^2 cm^2 * 1 cm = 9π cm^3, which is approximately 28.27 cm^3.
The polar radius is about 454.7km, with the equatorial radius about 487.3km. Using the formula; 4/3 x Pi x Er squared x Ep Where Er is equatorial radius and Ep polar radius, the volume of Ceres is around 4.523 x 10 to the 8 cubic km.
The mantel is the layer below the crust. It consists of molten rock and it has a low velocity and therefore can be poured easily.
the volume of a cylinder is (pi) x (r squared) x (h) where r = radius and h = height. unfortunately you dont say if the height is 5 or 6mm! if we take it that it is 5mm high, then- vol = 3.142 x 3 x 3 x 5 = 141.39mm if it is 6mm high, then- vol = 3.142 x 2.5 x 2.5 x 6 = 117.825mm
The layer of oil was poured on the surface of the water to create a barrier that prevents evaporation and to study interfacial tension between the two liquids. This can help to observe any interactions or reactions that may occur at the interface.
No, it is not. It is finite in volume.
According to Pilling-Bedworth rule, if the volume of oxide layer formed is greater than the volume of the metal, the oxide layer is protective and non-porous. However if the oxide layer formed has volume lesser than that of the underlying metal then the oxide layer is porous and non-protective.
To calculate the volume of he first layer of a cube structure, simply multiply the length by the width by the height. The product gives you the total volume in the cube structure.
eat it.
The layer with the highest density would settle on the bottom of a graduated cylinder, as denser liquids tend to sink below less dense liquids.
A cube does not have layers.