To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.
An heptagon has 7 sides and 14 diagonals
A polygon with n sides has n(n-3)/2 diagonals. A heptagon has 7 sides giving it 7(7-3)/2 = 14 diagonals.
Using 1/2*(n2-3n) where n is the number of sides it will have 77 diagonals
The formula for finding the amount of diagonals in a polygon is n(n-3)/2. So 14(14-3)/2 = 77 Diagonals
A tetra-decagon is a 14 sided polygon having 77 diagonals
There are 77 diagonals
A polygon with 14 diagonals will have 7 sides
A 7 sided polygon has 14 diagonals
An heptagon has 7 sides and 14 diagonals
7
It will have 7 sides
1/2*(142-42) = 77 diagonals
Using the formula: 0.5*(142-42) = 77 diagonals
A polygon with n sides has n(n-3)/2 diagonals. A heptagon has 7 sides giving it 7(7-3)/2 = 14 diagonals.
Using 1/2*(n2-3n) where n is the number of sides it will have 77 diagonals
6 * * * * * No! The number of diagonals in a polygon with n sides is 1/2*n*(n - 3). So when n = 7 this gives the number of diagonals in a heptagon is 14.
12 * * * * * Not so. A polygon with n sides has 1/2*n*(n - 3) diagonals. In this case, n = 7 and so there are 14 diagonals.