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To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.
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What polygon has twice as many diagonals as sides?
An heptagon has 7 sides and 14 diagonals
How many diagonals does a heptagon have?
A polygon with n sides has n(n-3)/2 diagonals. A heptagon has 7 sides giving it 7(7-3)/2 = 14 diagonals.
How many diagonals does a polygon with 14 sideshave?
Using 1/2*(n2-3n) where n is the number of sides it will have 77 diagonals
How many diagonals are in a 14 sided polygon?
The formula for finding the amount of diagonals in a polygon is n(n-3)/2. So 14(14-3)/2 = 77 Diagonals
How many diagonals does tetra-decagon have?
A tetra-decagon is a 14 sided polygon having 77 diagonals
