2400 square meters
Area of the rectangle: 9 times 8 = 72 square meters
The area of a rectangle (A) is the length of the rectangle multiplied by the height/width.A = 9 m x 8 m, so the area is 72 square meters.72 square meters
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
As a rectangle has four sides then 11 + 4 + 11 + 4 = 30 meters perimeter
If it was a square, which is a rectangle, the perimeter would be 24 meters . But it was a regular rectangle than it could be a few things actually , one of them would be 26 meters . Another would be 40 meters I think .
18 meters of fencing. You simply need to find the circumference of the rectangle.
The length of the field is 250 meters. As we know the field is a rectangle, you can divide the amount of fencing in 2, which would be 400 meters. This will provide you with enough fencing for one end and one side. To determine the actual length of the side you would take your 400 meters and subtract the end length which is 150 meters, leaving you with a side length of 250 meters.
2(352.3)+2(127.2) = 959 meters of fencing is needed
36
The rectangle with the smallest perimeter is a square. In this case each side of the square will be 60 m and will require 240 m of fencing. The less square the rectangle is, the larger the perimeter: Try it with a rectangle 40 x 90. This will require 260 m. Try 30 x 120: this needs 300 m...
The length of the rectangle is 27 meters and the width is 19 meters.
The pieces would be arranged 4 by 4, That is 20 meters by 20 meters or 400 square meters.
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
32m2 = 2m x 16m(width)Length(a) x width (16m) = 288m2288m2 / 16m = 18m
First, we need to find the other side of the rectangular (shaped like a rectangle). By using the Pythagorean theorem we have: 50^2 - 48^2 = side^2 = 196. So, this side is 14 m. Now, that we have both the length and the width, we can find the area of the rectangle, which is 48 x 14 = 672. Thus, the area of the rectangle is 672 m^2.
how much fencing will be needed to fence a property 6.5 meters long and 3 meters wide?
Rectangle that measures 20 meters by 15 meters