The area of a trapezoid is equal to one half the product of the length of its height and the sum of its bases. So we have:
A = (1/2)(h)(B + b) substitute what you know into the formula
45 cm^2 = (1/2)(h)(12 cm + 6 cm)
45 cm^2 = (1/2)(h)(18 cm)
45 cm^2 = (h)(9 cm) divide by 9 cm to both sides
5 cm = h
Thus, the height is 5 cm.
The area of a parallelogram with base 18cm and perpendicular height 18cm is 324 cm2
0.72 cm2
Base = 8, Height = 15
Vertical height = sqrt{142 - [(22-9)/2]2} = sqrt{142 - 6.52} = sqrt(153.75) = 12.40 cm (approx).So area = 1/2*(22+9)*12.40 = 192.19 cm2.Vertical height = sqrt{142 - [(22-9)/2]2} = sqrt{142 - 6.52} = sqrt(153.75) = 12.40 cm (approx).So area = 1/2*(22+9)*12.40 = 192.19 cm2.Vertical height = sqrt{142 - [(22-9)/2]2} = sqrt{142 - 6.52} = sqrt(153.75) = 12.40 cm (approx).So area = 1/2*(22+9)*12.40 = 192.19 cm2.Vertical height = sqrt{142 - [(22-9)/2]2} = sqrt{142 - 6.52} = sqrt(153.75) = 12.40 cm (approx).So area = 1/2*(22+9)*12.40 = 192.19 cm2.
3 x 5 ie 15 cm2
Area = 1/2*(17+8)*6 = 75 cm2 Use Pythagoras' theorem to find the sloping side of the trapezoid: 62+92 = 117 and the square root of this is about 10.8 Perimeter = 17+8+6+10.8 = 41.8 cm
You can cut the tapered ends off of the trapezoid, and calculate the individual areas of the three pieces. The center piece is a rectangle, Length = 27, Height = H. Area = 27H. Each end is a triangle, Base = 2, Height = H. Area = (1/2 base) times (height) = 1H (Left-end triangle) + (center rectangle) + (right-end triangle) = 1H + 27H + 1H = 29H. 29H = 348 cm2 H = 348/29 = 12 cm
Area = 1443.376 cm2
180 cm2
17.5 cm2
The area of a parallelogram with base 18cm and perpendicular height 18cm is 324 cm2
Area = Base * vertical height = 8*14 = 112 cm2
volume_prism = area_base x height = 32 cm2 x 7 cm = 224 cm3
half the base an divide the area by that
volume_of_prism = area_of_base x height 275 cm3 = 25 cm2 x height => height = 275 cm3 / 25 cm2 = 11 cm
All you can say is ( for example) for an area of 7 cm2, that "the volume is 7 cm3 per cm height".
188.4 cm2