yes it is.. with 45 being the longest side..:)
No because it does not comply with Pythagoras; theorem if the lengths were 10, 24 and 26 then it would be.
3(16x-9)=48x-27 is the perimeter
drop a line from the vertex to the bottom line of the triangle you get a right angle triangle with side 6, 3 and x where x is the altitude of the triangle 6^2=3^2+x^2 use pythagoreus theorem 36=9+x^2 x=sqrt 27=3sqrt3=5.196cm
5
No.1 A right triangle with sides 6, 9 and 10.82 will have angles of 33.69 and 56.31 sin(33.69) = 0.554699 cos(33.69) = 0.832051 tan(33.69) = 0.666665 cot(33.69) = 1.500004 sec(33.69) = 1.201849 csc(33.69) = 1.802779 sin(56.31) = 0.832051 cos(56.31) = 0.554699 tan(56.31) = 1.500004 cot(56.31) = 0.666665 sec(56.31) = 1.802779 csc(56.31) = 1.201849 No.2 A right triangle with sides 16.97, 21 and 27 will have angles of 38.94 and 51.06 sin(38.94) = 0.628506 cos(38.94) = 0.777805 tan(38.94) = 0.808052 cot(38.94) = 1.237545 sec(38.94) = 1.28567 csc(38.94) = 1.591074 sin(51.06) = 0.777805 cos(51.06) = 0.628506 tan(51.06) = 1.237545 cot(51.06) = 0.808052 sec(51.06) = 1.591074 csc(51.06) = 1.28567 No. 3 A right triangle with sides 3, 6.32 and 7 will have angles of 25.38 and 64.62 sin(25.38) = 0.42862 cos(25.38) = 0.903485 tan(25.38) = 0.474407 cot(25.38) = 2.107894 sec(25.38) = 1.106825 csc(25.38) = 2.33307 sin(64.62) = 0.903485 cos(64.62) = 0.42862 tan(64.62) = 2.107894 cot(64.62) = 0.474407 sec(64.62) = 2.33307 csc(64.62) = 1.106825
No because it does not comply with Pythagoras; theorem if the lengths were 10, 24 and 26 then it would be.
True because it complies with Pythagoras' theorem.
false In order for this to be a right triangle, the sum of the squares of the two shorter sides would have to equal the square of the longest side. 102=100 242= 576 272=729 102+242= 676, which does not equal 272=729, so a triangle with these lengths is not a right triangle.
FalseImproved Answer:-True because it complies with Pythagoras' theoremNew & Improved, 40% Whiter Answer :-False because it does not comply with the Pythagorean Theorem.(10, 24, and 26 do, but 10, 24, and 27 don't.)
To check whether it is possible to have a triangle with side lengths 4cm, 13cm, and 14cm, we use a special rule.The rule is: If you take any two sides of a triangle and add their lengths, the sum of the lengths must be greater than the third side.Test this triangle. 4+13=17, which is bigger than 14. 14+4=18, which is bigger than 13. 13+14=27, which is greater than 4.The rule works for all side combinations, so it is possible to have a triangle like this.So the answer is: yes, you can have a triangle of side lengths 4cm, 13cm, 14cm. (Note that the lengths do not have to be in centimeters, for example they can be 4m, 13m, and 14m)
You can find relative lengths (compared to each other), but not absolute ones (what they actually are).
There is no answer to this question. The angle between the two sides needs to be known.
If the sides of a right angle triangle are 27 ft and 36 ft then by using Pythagoras' theorem its hypotenuse works out as 45 ft
27+27+27=81 The equation for the perimeter an equilateral triangle is "side + side + side". And since it is an equilateral all the sides are the same length.
9+9+9 = 27 cm
It is: 3*9 = 27 inches
Let x be the length measure of the shortest side, so the length measure of two other sides are x + 2, and x + 4 x + (x + 2) + (x + 4) = 27 3x + 6 = 27 subtract 6 to both sides 3x = 33 divide by 3 to both sides x = 11 Thus the shortest side is 11 inches,