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We know that,

Circumference of the wire = 2πr

Thus, resistance per unit volume of the wire = 4/2πr = 2/πr

So, resistance of the specimen = 2/πr × 2r = 4/π

And resistance of the halves of the wire = 2/πr × πr = 2

Now, Equivalent resistance will be decided as 4/(4+π) as 4/π,2,2 are in parallel combination.

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