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96 degrees
Let theta represent the measure of the angle we are trying to find and theta' represent the measure of its supplement. From the problem, we know:
theta=theta'+12
Because supplementary angles sum to 180 degrees, we also know:
theta+theta'=180
Substituting the value from theta in the first equation into the second, we get:
(theta'+12)+theta'=180
2*theta'+12=180
2*theta'=180-12=168
theta'=168/2=84
Substituting this value for theta' back into the first equation, we get:
theta+84=180
theta=180-84=96
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The supplement of an angle is 20 degrees more than three times the angle itself Find the angle and its supplement?
180-20=160
What it supplement of a 113 degrees triangle?
be more specific. the supplement angle is 67 supplement angle are two numbers to equal that
An angle that is the supplement of an acute angle must be what?
If one angle is the supplement of another, we know that their sum is 180 degrees.So let one angle be A and the supplement be B. We know the measure of A+B=180.If A is acute that means its measure is less than 90 degrees. The supplement must therefore have measure more than 90 degrees. We could say the supplement of an acute angle must be an obtuse angle. Remember obtuse angle is one that less than 180 degrees and more than 90.
What is the supplement of the angle whose measure is 15 degrees?
It is 165 degrees because 165+15 = 180 degrees
Find Angle t if angle t is 20 more than four times its supplement?
Find the measure of the angle T, if the measure of the angle T is 20 more than four times its supplement. The supplement of T = (180-T) Write an equation for the statement: "angle T is 20 more than four times its supplement." T = 4(180-T) + 20 T = 720 - 4T + 20 T + 4T = 720 + 20 5t = 740 T = T = 148 degrees Check solution in original equation: 148 = 4(180-148) + 20 148 = 4(32) + 20 148 = 128 + 20
