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You can deduce that its height is 3, since the perpendiculars dropped from the shorter base create a central rectangle and two identical, right, isosceles triangle with base and height 3.

3(9+15)/2=36

We know the piece of the base is 3 because we subtract 9 (top base) from 15 (bottom base) and that gives us 6, then divide that in half because there are 2 triangles, so we get 3

this only works for isosceles trapezoids

Then because the triangles on the sides are isosceles, the length of their bases is the same so if the horizontal base is 3, then the vertical base is also 3, which is the height of the trapezoid

Area = average of bases times height

Area = (base 1 + base 2)/2 x height

Area = (15 + 9)/2 x 3

Area = 24/2 x 3

Area = 12 x 3 = 36

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Q: An isosceles trapezoid has base angles of 45 degrees and bases of lengths 9 and 15 The area of the trapezoid is?
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