To figure out what the measure of the base angles in an isosceles triangle are, it is important to first understand several things about an isosceles triangle.
1. A triangle has 180 degrees.
2. An isosceles has two equal sides, which means that it also has two equivalent angles.
3. In knowing at least any one angle of an isosceles triangle, it is possible to figure out the other two.
Since the base angles are unknown in this question, and they are equivalent to one another, it is a simple algebraic problem.
180 - 70 = 2A
180 is the number of degrees in a triangle
70 is the number of degrees taken up by angle C, with angles A and B being the equivalent base angles.
2a is the double of one base angle. Let's solve.
180 - 70 = 2A
110 = 2A
110/2 = A
55 = A
The measure of each base angle is 55.
55 degrees
The base angles will have equal angles of 50 degrees
70
180 - 2*52 = 76 both base angles are equal (property of an isosceles triangle) and total angles is 180
Each base angle is 62.5 degrees
51 degees
80 degrees
55 degrees
(180 - 78) / 2...
130 degrees is the measure of the base angles of an isosceles triangle whose vertex has a measure of 50 degrees.
57.5 degrees
180 - twice 42
The base angles of an isosceles triangle are congruent. The vertex angle of an isosceles triangle is not necessarily congruent to the base angles.
The measure of each base angle in an isosceles triangle can be calculated by dividing the total angle sum by the number of base angles, i.e., (180 - vertex angle) / 2. In this case, each base angle of the isosceles triangle would measure (180 - 38) / 2 = 71 degrees.
20 degrees
The base angles will have equal angles of 50 degrees
40