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Yes. To prove it, note that if they satisfy A2 + B2 = C2 then they can form a right triangle. Well, 32=9 and 42=16 and 52=25 and 9+16=25 . So 3, 4, and 5 do in fact work fine. In high-school geometry, this kind of triangle has a special name. It's called a "Three four five right triangle". Duh.

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Anonymous

4y ago
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Q: Can 3m 4m 5m represent sides of a right triangle?
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