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Yes. To prove it, note that if they satisfy A2 + B2 = C2 then they can form a right triangle. Well, 32=9 and 42=16 and 52=25 and 9+16=25 . So 3, 4, and 5 do in fact work fine. In high-school geometry, this kind of triangle has a special name. It's called a "Three four five right triangle". Duh.

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Q: Can 3m 4m 5m represent sides of a right triangle?
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What is the area of 3m 3m 9m?

It is not possible to answer the question. There are three measures, but they cannot form a 2D shape - a triangle. If they are the lengths of sides of a solid figure, there is no information as to what shape that figure is - a cuboid or a parallelepiped.


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