Yes. To prove it, note that if they satisfy A2 + B2 = C2 then they can form a right triangle. Well, 32=9 and 42=16 and 52=25 and 9+16=25 . So 3, 4, and 5 do in fact work fine. In high-school geometry, this kind of triangle has a special name. It's called a "Three four five right triangle". Duh.
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It is: 0.5*6*3 = 9 square meters
This is not the question I was looking for.1Record the length and width of a square or rectangle. Substitute your measurements into the formula "length x width" to solve for area. For example, a rectangle with a length of 7 meters (m) and a width of 3m has an area of: 7m x 3m = 21m^2 (21 meters squared, or 21 square meters).2Use the formula "(base x height)/2" to find the area of a triangle. A triangle with a height of 7m and a base of 3m has an area of 7m x 3m = 21m^2, divided by two equals 10.5m^2.
3 x 7 sq m
The perimeter of a rectangle is calculated by adding the lengths of all its sides. In this case, the length is 12m and the width is 3m. Therefore, the perimeter would be 2(12m) + 2(3m) = 24m + 6m = 30m.
area parallelogram = length of side x height between parallel sides ⇒ 33.75 m2 = side x 3m ⇒ side = 33.75 m2 ÷ 3m = 11.25 m