No, it is not possible.
All angles of a parallelogram are not necessarily congruent. A parallelogram means that the opposite sides run in straight lines that don't intersect. An example is a rectangle or square. Length of sides DO NOT determine if opposite angles are congruent. As long as opposite sides do not intersect each other at any point (if you continue to draw the lines), then the angles diagonal from each other are the same.
This describes a rectangle. It has four sides, four right angles, and its opposite sides are parallel, but the adjacent sides are not equilateral (congruent). If a quadrilateral has four right angles, it will be either a square or a rectangle. With the four right angles, it cannot be anything else. Draw a line segment. Now draw another one at a right angle to the first one. Now draw a third line segment at a right angle from the second one, and make this one the same length as the first one. Then draw the last segment to close the figure. It will have fours sides, and it will have four right angles. It will also have two pairs of parallel sides.
It's a square.
you can`t if you did it would be a square
A rhombus (pushed over square) will give you 2 pairs of parallel, congruent sides, 2 acute angles and 2 obtuse angles.
Yes. If you don't believe me, then you can draw one yourself.
It cannot. There is no way to draw a quadrilateral where 3 sides are congruent.
Squares are special cases of rhombuses, ones in which all the internal angles are the same (90°). So no, you cannot draw a square that is not a rhombus. It's a bit like trying to draw a square that is not a quadrilateral. Squares are special cases of quadrilaterals.
No, you cannot.
draw a line in btw , and divid it into 2 parts ! Then u will no wat to do !
No, it is not possible.
All angles of a parallelogram are not necessarily congruent. A parallelogram means that the opposite sides run in straight lines that don't intersect. An example is a rectangle or square. Length of sides DO NOT determine if opposite angles are congruent. As long as opposite sides do not intersect each other at any point (if you continue to draw the lines), then the angles diagonal from each other are the same.
Yes. A rhombus is a "squashed" square in that every side is equal in length but only opposite angles are equal. The square is a special case of a rhombus where not only are opposite angles equal, but all 4 angles are equal. All squares are rhombuses but not all rhombuses are squares.
facts about rhombus's: 1) a rhombus is a parallelogram with all four sides of equal length. 2) the sum of the angles inside a 4-sided polygon is 360 degrees. 3) in a rhombus the two opposing corners must be the same angle in order for (1) to be true. therefore: the only way to draw a rhombus with 2 right angles, is to actually draw one with 4 right angles a.k.a. a square
no a square is a rhombus with equal sides and angles are all 90 degrees
This describes a rectangle. It has four sides, four right angles, and its opposite sides are parallel, but the adjacent sides are not equilateral (congruent). If a quadrilateral has four right angles, it will be either a square or a rectangle. With the four right angles, it cannot be anything else. Draw a line segment. Now draw another one at a right angle to the first one. Now draw a third line segment at a right angle from the second one, and make this one the same length as the first one. Then draw the last segment to close the figure. It will have fours sides, and it will have four right angles. It will also have two pairs of parallel sides.