No.
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If 1 or 2 of the obtuse angles are 'bent into' the hexagon then you can do it.A hexagon has 720° sum of interior angles. If you have 2 right angles, then that's 180°, leaving 540° to be distributed over four angles. If the two acute angles are 89°, then that leaves 362° to be divided between two angles, so at least one of these two angles will need to be greater than 180°. Below is my text graphics attempt of one possibility (ignore the 'dot'). Note that both of the obtuse angles are greater than 180°:|\_/||__.|Look at the related link to play with different angle possibilities for polygons.
They make a pair of acute angles and a pair of obtuse angles. In rotational order, the angles are acute, obtuse, acute, obtuse.
no all angles are acute.
A hexagon is any six-sided plane (two-dimensional) figure. A regular or equilateral hexagon is such a figure with all sides equal in length and all angles equal. The two conditions are independent:You can "squash" a regular hexagon to change the angles without changing the sides.You can also "stretch" or "squeeze" a regular hexagon to make one pair of sides at a time longer or shorter than the others.
No, a trapezoid cannot have two acute angles and two obtuse angles. By definition, a trapezoid has only one pair of parallel sides. In a trapezoid, the non-parallel sides are always supplementary, meaning they add up to 180 degrees. Therefore, having two obtuse angles would make it impossible for the other two angles to be acute and still satisfy the properties of a trapezoid.