Yes. The maximum area for a rectangle with a given perimeter is the square (in this case, 5 cm x 5 cm = 25 cm2), and any area between that and 0 is possible by slowly stretching out the square, increasing its length while decreasing its width.
If you'd like to figure out the dimensions of the rectangle with a perimeter of 20 and an area of 20 (I'll leave off the units for simplicity), we can use algebra:
Let x and y be the length and width. We know two things:
Area: xy = 20
Perimeter: 2x + 2y = 20
Solve the second equation for y and we get
y = 10 - x.
Substituting that in the first equation we get
x(10 - x) = 20
which turns into the quadratic equation
x2 - 10x + 20 = 0
Applying the quadratic equation, we get
x = 5 +/- sqrt(5), which gives us our two dimensions:
5 + sqrt(5) and 5 - sqrt(5)
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what is the perimeter of the parallelogram 20cm 30cm 17cm=100
Example: To find the perimeter of a rectangular box, with length as 6cm and Breadth as 4 cm, we need to use the formula, Perimeter of a Rectangle = 2 (L+B) = 2 ( 6 cm + 4 cm) = 2 × 10 cm = 20cm.
25 cm2
100 is the answer.
The area of square is : 400.0