10!
If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)
9_or_yes">9 or yesA+ = 12
It can be but need not be.
The area of the whole circle is PI x 6 squared which equals 36 PI. We can now use the ratio 30/36 = x/360 to find the angle (360 is the full angle if the circle, x is the angle of the segment, pi's cancell out) If we solve for x we get 300 degrees which is the angle we need. As for the length, the circles circumference is 12 PI (12 is the diameter). This means that 30/36= AB/12PI AB=10PI
angle BLD is 72 degrees.
For you A+ Cheaters ;D it's 50!
67 degrees
The answer is "No Solution" because there is not enough information.
12
More information is needed.
32 degrees
No. But they add up to 180 degrees.
The square root of 149 (7 squared plus 10 squared equals 149).
If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)
9_or_yes">9 or yesA+ = 12
The measure of the angle formed between a tangent and a chord at the point of contact is equal to half the measure of the intercepted arc on the circle. Given a tangent-chord angle of 162 degrees, the measure of the intercepted arc ( AB ) (arc ( AB ) is represented as ( \angle CAB )) would be twice that angle, which is ( 2 \times 162 = 324 ) degrees.
It can be but need not be.