Only for a square or rhombus (diamond shape). The diagonals of a rectangle bisect each other, but are not perpendicular and do not bisect the opposite angles they join.
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No.
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
Only if the parallelogram is in the form of a rhombus will its diagonals bisect each other at right angles
A quadrilateral is a parallelogram if and only if its diagonals bisect each other (this should be in any geometry book)
No but the diagonals of a square bisect each other at right angles