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Given: a square with side = s and a circle with radius = s (radius is equal to the length of the side of the square) Areasquare = side squared = s2 Areacircle = pi times the square of the radius = pi times s2 Areasquare : areacircle = s2 : pi s2 = 1 : pi (The ratio is one to pi.)
If you visualize the cone by cutting it vertically (with a plane perpendicular to the base), you can construct a right triangle to represent the radius, altitude, and slant height. This triangle has legs of 7 (the radius) and 19 (the altitude). Its hypotenuse represents the slant height. We can then use the Pythagorean theorem to solve for the slant height: 72 + 192 = s2 72 + 192 = s2 410 = s2 s = √(410) s ≈ 20.24 Therefore the cone has a slant height of √(410), or approximately 20.248456731316586933246902289901 units.
the Regular hexagon : Area=(1/2)*(radius of the inscribed circle)*perimeter units2 The irregular hexagon : Area can be computed by the scalene triangle method. from one of the points to the other vertexes,you get 3 diagonals and hence three scalene triangle. hence use the area of a scalene triangle=sqrt(s (s - s1) (s - s2) (s - s3)) units2 where s=(s1+s2+s3)/2
No, only if the diameter is bigger than the radius is the radius smaller than the diameter.
It gets bigger.