Considering that any two edges that meet at 90 degrees are perpendicular, there are 3 per corner, giving a total of 24.
Any shape with straight edges can have perpendicular edges.
False, the prism can be of any length.
Infinitely many. Every possible triangle can be used to generate a triangular prism, and in each case, the prism can have any one of infinitely many lengths.
A triangular prism, a triangle base and three triangular faces (a tetrahedron)The figures below do not strictly have a "base" but they are composed entirely of trianglesAn octohedron (eight sides)An isocahedron (20 identical equilateral triangular faces, 30 edges and 12 vertices)Any of a number of deformations of the above
Triangular Prisms don't have any vertical edges
A triagular prism has 5 faces, 9 edges and 6 vertices
It need not have any. A right triangular prism has 12 pairs but could have 14.
Considering that any two edges that meet at 90 degrees are perpendicular, there are 3 per corner, giving a total of 24.
A triangular prism has two triangular faces, a rectangular prism does not have any.
It is a triangular prism and any triangular prism is a wedge.
Any shape with straight edges can have perpendicular edges.
They are both polyhedra. They both have faces that have 3 or 4 edges, and not any other.
"Triangular" is an adjective and so cannot have any of anything. You need a noun to go with the adjective to make it a subject of the question: such as triangular lamina, or triangular pyramid or triangular prism, or triangular dipyramid or whatever. And in each case, the answer will be different!
the number edges of the base of a pyramid is onr more than the number of faces * * * * * The question had nothing to do with pyramids and, in any case, the answer is wrong! There are different formulae for different aspect of a triangular prism: its volume, surface area, numbers of edges, faces, or vertices. there is no single formula.
Triangular Prisms don't have any vertical edges
None of the edges of a triangular pyramid is parallel to any of its other edges.