yes it does
Considering that any two edges that meet at 90 degrees are perpendicular, there are 3 per corner, giving a total of 24.
Any shape with straight edges can have perpendicular edges.
False, the prism can be of any length.
Infinitely many. Every possible triangle can be used to generate a triangular prism, and in each case, the prism can have any one of infinitely many lengths.
A triangular prism, a triangle base and three triangular faces (a tetrahedron)The figures below do not strictly have a "base" but they are composed entirely of trianglesAn octohedron (eight sides)An isocahedron (20 identical equilateral triangular faces, 30 edges and 12 vertices)Any of a number of deformations of the above
Triangular Prisms don't have any vertical edges
A triagular prism has 5 faces, 9 edges and 6 vertices
It need not have any. A right triangular prism has 12 pairs but could have 14.
Considering that any two edges that meet at 90 degrees are perpendicular, there are 3 per corner, giving a total of 24.
A triangular prism has two triangular faces, a rectangular prism does not have any.
It is a triangular prism and any triangular prism is a wedge.
Any shape with straight edges can have perpendicular edges.
They are both polyhedra. They both have faces that have 3 or 4 edges, and not any other.
Triangular Prisms don't have any vertical edges
the number edges of the base of a pyramid is onr more than the number of faces * * * * * The question had nothing to do with pyramids and, in any case, the answer is wrong! There are different formulae for different aspect of a triangular prism: its volume, surface area, numbers of edges, faces, or vertices. there is no single formula.
"Triangular" is an adjective and so cannot have any of anything. You need a noun to go with the adjective to make it a subject of the question: such as triangular lamina, or triangular pyramid or triangular prism, or triangular dipyramid or whatever. And in each case, the answer will be different!
None of the edges of a triangular pyramid is parallel to any of its other edges.